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nalin [4]
2 years ago
9

Hydrogen bonding is --

Chemistry
1 answer:
Virty [35]2 years ago
4 0
Hydrogen bonds are a strong attractive force, since they are less stronger than ionic bonds.
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What comes last in the scientific method
azamat
Hypothesis


Therefore the last step in the scientific method is proposing a hypothesis or obtaining a conclusion
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Which of the following objects would float when placed in water? (Note: 1 mL 1 cm+3)*
liraira [26]

Only an apple will float when placed in water.

An object will float in water if its density is <em>less than that of water</em> (1.0 g/mL).

An object will sink in water if its density is <em>greater than that of water</em>.

Thus, solid objects made of <em>gold, iron, or rubber</em> will all sink in water.

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The reaction na 3po 4( aq) 3 agno3( aq) → ag 3po 4( s) 3 nano 3( aq) is best classified as a(n):_____.
Ugo [173]

The reaction  Na_{3} PO_{4} ( aq) +3AgNO_{3} (aq) → Ag_{3} PO_{4} ( aq) +3NaNO_{3} (aq) is best classified as double displacement reaction.

Those reaction in which two compounds react by exchanges of ions to form two new compounds is called  double displacement reaction. The easiest way to identify double displacement reactions is to check to see whether the cations exchanged anions with each other  or not . Always balanced chemical equation is used to determine.

There are three types of double displacement reaction which is given as,

  1. Precipitation
  2. Neutralization
  3. Gas formation

The real world example of double displacement reaction is combining vinegar and baking soda to create homemade volcano.

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6 0
1 year ago
The density of pure diamond is 3.5 g/cm°. What is the volume of a diamond with a mass of 0.25 g?
ValentinkaMS [17]

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3 0
2 years ago
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A student ran the following reaction in the laboratory at 671 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 7.33×10-2 moles of N
vaieri [72.5K]

Answer:

Kc = 8.05x10⁻³

Explanation:

This is the equilibrium:

                 2NH₃(g)   ⇄     N₂(g)     +     3H₂(g)

Initially       0.0733

React         0.0733α          α/2                3/2α

Eq     0.0733 - 0.0733α    α/2                0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682

N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

Kc= [N₂] . [H₂]³ / [NH₃]²

Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³

3 0
3 years ago
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