The quantity of carbon tetrachloride, CCl₄ she will use to make her conversion is molar mass
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
<h3>How to determine the mole of CCl₄</h3>
- Mass of CCl₄ = 30 g
- Molar mass of CCl₄ = 12 + (35.5×4) = 154 g/mol
- Mole of CCl₄ =?
Mole = mass / molar mass
Mole of CCl₄ = 150 / 154
Mole of CCl₄ = 0.974 mole
Thus, we can see that the molar mass of CCl₄ is needed to obtain the number of mole.
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Answer:
10/24
Simplified: 5/12
Explanation:
Well first, let's convert years into months
1 year = 12 months which means 2 years = 24 months
In fraction form we would write this as 10/24
If the question asks for it to be simplified, then simply
Both 10 and 24 evenly fit 2
Therefore, divide both the numerator and the denominator by 2
10 ÷ 2 / 24 ÷ 2
5/12
This can no longer be simplified
½H2(g) + ½I2(g) → HI(g) ΔH = +6.2 kcal/mol
or...
½H2(g) + ½I2(g) + 6,2kcal/mole → HI(g)
________
21.0 kcal/mole + C(s) + 2S(s) → CS2(l)
or...
C(s) + 2S(s) → CS2(l) ΔH = +2,1 kcal/mole
_________
ΔH > 0 ----------->>> ENDOTHERMIC REACTIONS
3
Species
Genetic diversity
Ecosystem diversity
You have to calculate the oxidation estates of the atoms in each compound.
I will start with K2Cr2O7 because I believe that Cr is the best candidate to reduce its oxidation number in 3 units.
In K2Cr2O7:
- K has oxidation state of 1+, then K2 has a charge of 2* (1+) = 2+.
- O has oxidation state of 2*, then O7 has a charge of 7* (2-) = 14-.
That makes that Cr2 has charge of 14 - 2 = +12, so each Cr has +12/2 = +6 oxidation state.
In Cr2O3:
- O has oxidation state of 2-, then O3 has charge 3 * (2-) = - 6
- Then, Cr2 has charge 6+, and each Cr has charge 6+ / 2 = 3+.
So, we have seen that Cr reduced its oxidation state in 3 units, from 6+ to 3+.
Answer: Cr has a change in oxidation number of - 3.
