Answer:
2.5
Explanation:
Momentum = Mass × Velocity
The magnitude of normal force that floor exerts on chair is 100.83N
<u>Explanation:</u>
Given:
Weight of chair, W = 75N
Applied force, F = 42N
Angle, θ = 38°
Normal force, n = ?
We know,
Vertical component of the force = F sinθ
= 42 X sin38°
= 42 X 0.615
= 25.83N
Total normal force acting on the chair = 75N + 25.83N
= 100.83N
Therefore, the magnitude of normal force that floor exerts on chair is 100.83N
Answer:
m/min
Explanation:
You have to use the volume of a cone, which is:
where r is the radius of the base and h is the height.
In this case, r=5 and h=10. The radius can be written as r=h/2
Replacing it in the equation:
(I)
The rate of the volume is the derivate of volume respect time, therefore you have to perform the implicit differentiation of the previous equation and equal the result to 3.14 m³/min
Replacing dV/dt= 3.14, h=7.5 and solving for dh/dt, which represents how fast the level is rising:
Multiplying by 16/225π both sides:
m/min
Weight will be 9.8 N
4.0 m in length
<span>A naturally occurring force related to two bodies in motion is frictional force. Friction is a type of force which includes two bodies resisting each other –either motion of solid surfaces, fluid layers, material elements and compounds gliding against each other. They key point of this frictional force is that the two forces are in the opposite point of direction with each other. For example, when you are cold, as you rub your hands together notice that when your right hand is going upward, your left hand is downward and thus creates heat. That is one type of friction force outcome, the heat.<span>
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Okay so here's the approach I took:
The potential difference in each of the circuits must be the same so if we derive equations for both the potential differences we can set them equal to each other and solve for R1:
In the first circuit
V = 2.2(R1)
In the second we have to find the equivalent resistor, since they are connected in series:
1/R1 + 1/R2 + 1/R3... = Rt
We have R2 so...
1/R1 + 1/3.1 = Rt
1/R1 + 0.323 = Rt
So...
V = 1.4(1/R1 + 0.323)
Set those equal:
2.2R1 = 1.4(1/R1 + 0.323)
2.2R1 = 1.4(1/R1) + 0.4522
Now multiply everything by R1 so we can combine like terms:
2.2R1^2 = 1.4 + 0.4522R1
Isolate to form a quadratic
2.2R1^2 - 0.4522R1 - 1.4 = 0
Solving this quadratic:
R1 = 0.90708 or R1 = -0.701
Since R cannot be negative
R1 = 0.907 ohms