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Natali5045456 [20]
3 years ago
8

PLEASE HELP WILL GIVE 30 POINTS

Physics
2 answers:
Sholpan [36]3 years ago
7 0

Answer:

I think its c

Explanation:

I hope this helps u and u get it right :D

BabaBlast [244]3 years ago
5 0
I think the answer is B
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What are cirrus.cirrostratus. And cirrocumulus clouds made up of
Irina-Kira [14]
<span><span>1.       </span>All clouds are made up of tiny ice crystals or small water droplets that form together with a dust on the atmosphere.
Cirrus, cirrostratus and cirrocumulus are made up of ice crystals. It forms when the water vapor goes condensation at high altitudes in where the pressure on the atmosphere reaches the point from 600 mbar at 4000 meter above the sea level up to 200mbar at 12 000m above sea level. These clouds form thunderstorms, cyclones and contrails (a manmade cloud).</span> <span>

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3 0
3 years ago
If you sleep 33% in a day, how many hours is that?
lesantik [10]

In this question, one has to carefully understand that the total number of hours in the day can never be more that 24 hours. based on this important fact the answer to the question can be very easily deduced. The only requirement is calculating perfectly.
Number of hours in a day = 24 hours
Percentage of hours of sleep in a day = 33%
Amount of sleep in the day = (33/100) * 24
                                             = 7.92 hours
So 33% of sleep in a day is equal to 7.92 hours. I hope this answer has helped you. In future you can keep the procedure in mind for solving such problems.
5 0
4 years ago
The length of a certain wire is doubled and at the same time its radius is also doubled. What is the new resistance of this wire
Leto [7]

Answer:

R' = R/2

Therefore, the new resistance of the wire is twice the value of the initial resistance.

Explanation:

Consider a wire with:

Resistance = R

Length = L

Area = A = πr²

where, r = radius

ρ = resistivity

Then:

R = ρL/A

R = ρL/πr²   --------------- equation 1

Now, the new wire has:

Resistance = R'

Resistivity = ρ

Length = L' = 2 L

Radius = r' = 2r

Area = πr'² = π(2r)² = 4πr²

Therefore,

R' = ρL'/πr'²

R' = ρ(2 L)/4πr²

R' = (1/2)(ρL/πr²)

using equation 1:

<u>R' = R/2</u>

<u>Therefore, the new resistance of the wire is twice the value of the initial resistance.</u>

4 0
3 years ago
(a) Calculate the magnitude of the angular momentum of the earth in a circular orbit around the sun. Is it reasonable to model i
Anni [7]

Answer:

(a) L=2.6742\times 10^{40}\, kg.m^2.s^{-1}

(b) L_s=7.07 \times 10^{23} \, kg.m^2.s^{-1}

Explanation:

<u>For Earth we have:</u>

  • mass of earth, m_E=5.97\times 10^{24}\, kg
  • radius of earth, R_E=6.38\times 10^6m
  • orbital radius, r=1.5 \times 10^{11}m
  • period of rotation, t_{rot}=24h=86400\, s
  • period of revolution, t_{rev}= 1 yr=3.156\times 10^7 s

(a)

Angular momentum, L=?

∵L=I.\omega...............................(1)

For a particle of mass m moving in a circular path at a distance r from the axis,

I=m.r^2

& v=r.\omega

Putting respecstive values in eq. (1)

L=m_E\times r^{2}\times \omega

L=5.97\times 10^{24}\times (1.5 \times 10^{11})^2\times \frac{2\pi}{3.156\times 10^7}

L=2.6742\times 10^{40}\, kg.m^2.s^{-1}

To model earth as a particle is  reasonable because the distance between the sun and the earth is very large s compared to the radius if the earth.

(b)

For a uniform sphere of mass M and radius R and an axis through its center,  I=\frac{2}{5}M.R^2

using eq. (1)

L_s=(\frac{2}{5}m_E.R_E^2) \omega

L_s=\frac{2}{5} \times 5.97\times 10^{24} \times 6.38\times 10^6\times \frac{2\pi}{86400}

L_s=7.07 \times 10^{23} \, kg.m^2.s^{-1}

6 0
3 years ago
A 1.5m wire carries a 2 A current when a potential difference of 88 V is applied. What is the resistance of the wire?
GalinKa [24]

Answer:

44 Ohms

Explanation:

Use Ohm's law:

(Resistance) = (Voltage) / (Current)

(Resistance) = 88V / 2 A = 44 Ohms

6 0
3 years ago
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