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andrew-mc [135]
4 years ago
14

A force of 18 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i

t from its natural length to 14 in. beyond its natural length?
Physics
1 answer:
dybincka [34]4 years ago
5 0

Answer:

Explanation:

Given

Force=18lb

extension=8in

Using Hooke's law to get the spring constant(k)

F=ke

Then,

K=f/e

K=18/8

K=2.25lb/in

Work done by spring is given by

W=1/2Fe

Or W=1/2ke²

Then,

Work done in stretching the spring to 14in

W=1/2ke²

W=0.5×2.25×14²

W=220.5lbin

1 Inch-pounds Force to Joules = 0.113J

Then, to joules

W=0.133×220.5

W=29.33J

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Answer:

Distance, d = 6.75 meters

Explanation:

Given that,

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We need to find the distance covered by the car during this time. The product of speed and the time taken by the car is called the distance covered by the it. Mathematically,

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Answer:

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8 0
3 years ago
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Answer:

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Explanation:

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