Input = 2,150 J; Output = 750 J
The efficiency of the engine = Output / Input = 750 J / 2,15 J = 0.3488
Answer: 0.3488 or 34.88 %
Answer:
.25 Hz
Explanation:
Period = 4 sec
freq = 1/p = 1/4 hz = .25 Hz
Answer:
The Carnot engine has zero power
Explanation:
Although theoretically the Carnot engine has more efficiency than the real engine. In practice however they tend to have zero power.
This is because all its processes are reversible (that is isothermic and adiabatic).
So the system equilibrates with its surroundings at every point in time. This makes work done very slow and the power generated is zero.
Carnot cycles requires attaining isothermal heat transfers which is quite difficult and take a long time. Also a pump that can handle liquid-vapour phase mixture will be required.
This is not practical.
Answer:
Correct answer: E₁ = 4 · E The electric field increased four times
Explanation:
Given:
E - Electric field at distance d
E₁ - Electric field at distance d₁
Q - Charge of an object
d₁ = (1/2) d
The formula by which the electric field is calculated is:
E = k Q / d²
Electric field at a distance d₁
E₁ = k Q / d₁²
We will form their quotient
E₁ / E = ((k Q) / d₁²) / ((k Q) / d²)
When the constant k and the charge Q is canceled we get:
E₁ / E = (1 / d₁²) / (1 / d²) = d² / d₁² = d² / ((1/2) d)² = 1 /(1/4) = 4
E₁ = 4 · E
The electric field increased four times
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