Correct question:
A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?
Answer:
the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Explanation:
Given;
length of solenoid, L= 0.35 m
diameter of the solenoid, d = 0.04 m
current through the solenoid, I = 5.0 A
magnetic field in the center of the solenoid, 2.8 x 10⁻² T
The number of turns per meter for the solenoid is calculated as follows;
Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.
Answer: W = 11340J
Explanation:
Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.
So this is the Formula: Power = Work / Time.
<u>Step 1:</u><em><u> Find the Formula</u></em>
P = W / T
<em><u>
</u></em>
<u>Step 2: </u><u><em>Make W the subject of the equation.</em></u>
W = PT
<u>Step 3:</u><u> </u><u><em>Given.</em></u>
P = 270 Watts, T = 42 seconds
<u>Step 4:</u><u><em> Substitute these values into equation 2
.</em></u>
W = 270(42)
<u>Step 5:</u><u> </u><u><em>Simplify.</em></u>
W = 11340J
The amount of work done was 11340.
~I hope I helped you! :)~
Answer:
option (C)
Explanation:
The amount of heat required to raise the temperature of substance of unit mass by unit degree is called specific heat of that substance.
Its SI unit is Joule / Kg °C.
Every material has a constant value of specific heat.
So, option (c) is correct.