D (-4; -2)
C (1; 2)
M (x; y)
DM+MC=CD
CM:MD=1:3
M: x= x(C)-(x(C) - x(D))/4=1-(1-(-4))/4=1 - (6/4)=1 - 1,5= - 0,5
M: y=y(C)-(y(C) - y(D))/4=2-(2-(-2))/4=2 - (4/4)=2 - 1=1
M(x; y)=M( -0,5; 1)
Answer:
B
Step-by-step explanation:
4 is the outlier
Answer:
60 mph
Step-by-step explanation:
We don't know how far Jimmy drives in each direction. Let this distance be d. Then, d = rate * time, and d = r(2 hours) (where r represents his speed while driving to the ferry).
But it's also true that d = (r - 20 mph)(3 hours).
Equating d = r(2 hours) and d = (r - 20 mph)(3 hours), we get:
r(2) = (r - 20)(3), or 2r = 3r - 60.
Subtracting 2r from both sides yields 0 = r - 60, so that r = 60 mph.
Jimmy averaged 60 mph on the outbound trip.
