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3 years ago

To solve x + 9 = 12,______9 from both sides of the equation.

Mathematics

1 answer:

Fantom [35]3 years ago

5 0

Answer:

Subtract 9 from both sides of the equation.

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1. What is the area of the figure below? (1 point)

maw [93]

Answer: 36in2

Step-by-step explanation:

A= base *height

=12*3

=36

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3 years ago

Ray UW is the angle bisector of VUT. If mVUW = (4x + 6)° and mWUT = (6x – 10)°, what is the measure of WUT? 32° 38° 48° 76°

stepan [7]

Ray UW bisect VUT it means it must be breaking them in two equal parts
VUT=VUW+WUV
and mVUW= mWUV
4x+6=6x-10
-2x=-16
x=8
mWUT=6x-10=6(8)-10=38°

Your answer is 38°

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3 years ago

Read 2 more answers

The sum of a number and five more than the number is less than fifteen

SIZIF [17.4K]

Answer: 5

Step-by-step explanation:

7 0

4 years ago

Need help on this please this one is hard for me

pshichka [43]

9514 1404 393

Answer:

y = -7x

Step-by-step explanation:

The line goes through the origin, so the y-intercept is b=0.

The line goes through the point (1, -7), so has a "rise" of -7 for a "run" of 1. The slope is ...

m = rise/run = -7/1 = -7

Then the slope-intercept form equation is ...

y = mx + b

y = -7x

6 0

3 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

So, the resultant makes an angle of $22.57^{\circ}$ with 9 lb force

Angle made with 13 lb force is $38^{\circ}-22.57^{\circ}=15.43^{\circ}$

7 0

3 years ago

Read 2 more answers

To solve x + 9 = 12,______9 from both sides of the equation.​

To solve x + 9 = 12,______9 from both sides of the equation.