<span>A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate?
</span>Newton's Second Law<span> of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:
</span>
F = ma = 67.0 kg (3.50 m/s^2) = 234.5 J
Answer: Blake may have a decreased chance of disease.
Explanation:
Research has shown that on average, a person who engages in more physical activity will live longer than a person who does not with one reason for this being that engaging in physical activity helps reduce the risk of diseases such as; heart disease, diabetes, and many forms of cancer.
Obesity (risk factor) and high blood pressure are also reduced by engaging in physical activity.
Answer:
Approximately 
assuming no heat exchange between the mixture and the surroundings.
Explanation:
Consider an object of specific heat capacity 
and mass 
. Increasing the temperature of this object by 
would require 
.
Look up the specific heat of water: 
.
It is given that the mass of the water in this mixture is 
.
Temperature change of the water: 
.
Thus, the water in this mixture would have absorbed :
.
Thus, the energy that water absorbed was: 
.
Assuming that there was no heat exchange between the mixture and its surroundings. The energy that the water in this mixture absorbed, 
, would be the opposite of the energy that the metal in this mixture released.
Thus: 
(negative because the metal in this mixture released energy rather than absorbing energy.)
Mass of the metal in this mixture: 
.
Temperature change of the metal in this mixture: 
.
Rearrange the equation to obtain an expression for the specific heat capacity: 
. The (average) specific heat capacity of the metal pieces in this mixture would be:
.
Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
To learn more about Wavelength of the light refer to:
brainly.com/question/15413360
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