Hi there!
We can use the following equation to derive acceleration:
vf = vi + at, where:
vi = 0 m/s (starts from rest)
a = acceleration
time = time (sec)
Rewrite:
vf = at
Solve for acceleration:
vf/t = a
30/6 = 5 m/s²
Answer:
Explanation:
Given
length of ladder L=15 feet
velocity with which top is falling is 6 m/min
when bottom of ladder is at a distance of 12 ft away from wall then top of ladder from bottom is given by
From diagram
differentiating
Answer:
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