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garik1379 [7]
3 years ago
12

How could you prove there are 180° in any triangle?

Mathematics
1 answer:
klemol [59]3 years ago
5 0
If we add the interior and the exterior of the corner of a triangle we always get 180 degree
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Find the slope between the two points: (9,9) and (12,15)
grandymaker [24]
The slope formula is \frac{Y2-Y1}{X2-X1}. For the two points, (x,y). You can pick any of the Y and X from these two points, but only once. \frac{9-15}{9-12} = \frac{-6}{-3} = 2 or \frac{15-9}{12-9} = \frac{6}{3} = 2 and both will equal to. The answer for the slope is 2.
3 0
2 years ago
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The following table shows the data collected from a random sample of 100 middle school students on the number of hours they do h
vodka [1.7K]

Answer:960

Step-by-step explanation:

4 0
2 years ago
you are traveling to an island that is accesible only by boat. you plan to take one boat there and a different boat back. You'll
weqwewe [10]

\text{Answer: }\text{Distance traveled by steamboat}=20\text{ knots}\\\text{Distance traveled by yacht }=20+20=40\text{ knots}

Step-by-step explanation:

Since we have given that

Time taken by steamboat makes the trip=5 hours

Time taken by yacht makes the trip =2.5 hours

Since we have also given that

the yacht is 20 knots faster than the steamboat,

So let the speed of steamboat be x

Let the speed of yacht be x+20

Now,  we have given that both boats will travel the same distance ,

So,

\text{Distance traveled by steamboat}=\text{ Distance traveled by yacht}\\\\x\times 5=(x+20)\times 2.5\\\\5x=2.5x+50\\\\5x-2.5x=50\\\\2.5x=50\\\\x=\frac{50}{2.5}\\\\x=20\text{ knots}

Hence,

\text{Distance traveled by steamboat}=20\text{ knots}\\\text{Distance traveled by yacht }=20+20=40\text{ knots}

7 0
2 years ago
The function graphed is reflected across the x-axis to create a new function. Which is true about the domain and range of each f
serg [7]

Answer:

Domain stays the same while the range changes

Step-by-step explanation:

While reflecting cross x-axis, the x coordinates remains the same while the y-coordinate changes to its opposite.

=> x- coordinate = Domain

=> y-coordinate = Range

4 0
3 years ago
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An airplane is traveling at a speed of 240 miles/hour with a bearing of 110°. The wind velocity is 56 miles/hour at a bearing of
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Answer:

Actual speed = 288 miles per hour

Actual direction angle = 116.38^\circ

Step-by-step explanation:

"Bearing" is the relative position of an object outside the plane compared to the position of the plane.  

Heading the the direction the nose of the plane is pointing.  

Course is the direction that pilot wants the plane to go.  

Wind direction is always the direction the wind is blowing from.  

The airplane is traveling at a speed of 240 miles/hour with a bearing of 110°.  

If the plane is traveling with a bearing of 110° and the wind is blown at a bearing of 325°.  

 325^{\circ}- 110^{\circ} =225^{\circ}

215^{\circ}- 180^{\circ} =35^{\circ}

The Ground speed will be in excess of the airspeed and true direction will be south if the indicated heading.  

The tailwind component is:

56 cos (35^\circ)

And the cross wind component is:

56 sin (35^\circ)  


And that is,

C^2 = (286)^2 + (32)^2


c = 288

So the actual speed of the plane is 288 miles per hour.

The deviation in the direction is:

Let the direction angle be 'x'.

x = tan ^{-1}\left ( \frac{32}{286} \right )=6.38^\circ

So the actual direction angle is 110^\circ+ 6.38^\circ=116.38^\circ.

5 0
2 years ago
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