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lozanna [386]
3 years ago
7

Which example is a renewable energy source?

Chemistry
2 answers:
Nastasia [14]3 years ago
8 0
Sunlight because it’s continuous and we cannot run out of it
Ierofanga [76]3 years ago
4 0
Sunlight is collected from a renewable resource, which is naturally replenished one a human timescale
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What happens to energy and temperature when molecules collide
steposvetlana [31]

Answer:

As temperature increases, molecules gain energy and move faster and faster. Therefore, the greater the temperature, the higher the probability that molecules will be moving with the necessary activation energy for a reaction to occur upon collision.

Explanation:

hope this helps!

3 0
2 years ago
Why is HCI a strong acid and HCIO a weak acid?
valkas [14]

Strong Acid: dissolves and dissociates 100% to produce protons (H+) 1. seven strong acids: HCl, HBr, HI, HNO3, H2SO4, HClO4, & HClO3 2. ... Weak Acid: dissolves but less than 100% dissociates to produce protons (H+) 1.

4 0
2 years ago
Write a chemical equation for the dissolution of the AgCl precipitate upon the addition of NH,(aq).
Kobotan [32]

Explanation:

White precipitate of silver chloride get dissolves in excess ammonia to formation of complex between silver ions, chloride ions and ammonia molecules.

The chemical reaction is given as:

AgCl(s)+2NH_3(aq)\rightarrow Ag[(NH_3)_2]^+Cl^-(aq)

When 1 mole of silver chloride is added to 2 mole of an aqueous ammonia it form coordination complex of diaaminesilver(I) chloride.

7 0
2 years ago
What is the structural formula of 2-methylbutan-2-ol (sometimes called 2-methyl-2-butanol)?
grigory [225]
<span>The structural formula of 2-methylbutan-2-ol is in Word document below.
</span>2-methyl-2-butanol is organic compound and belongs to alcohols. Hydroxyl <span>functional group is on second saturated carbon atom of butane and also methyl group (-CH</span>₃) is on second saturated carbon atom of main chain (butane).<span>

</span>
Download docx
4 0
3 years ago
Read 2 more answers
Chemistry student needs of 55g acetone for an experiment. by consulting the crc handbook of chemistry and physics, the student d
sergeinik [125]

Answer:

             70.15 cm³

Solution:

Data Given;

                  Mass  =  55 g

                  Density  =  0.784 g.cm⁻³

Required:

                  Volume  =  ?

Formula Used:

                  Density  =  Mass ÷ Volume

Solving for Volume,

                  Volume  =  Mass ÷ Density

Putting values,

                  Volume  =  55 g ÷ 0.784 g.cm⁻³

                  Volume = 70.15 cm³

5 0
3 years ago
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