An object on top of a building has a GPE of 23,048j and a mass of 39kg, What is the height of the object
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Answer:
The mass of radon that decompose = 63. 4 g
Explanation:
R.R = P.E/(2ᵇ/ⁿ)
Where R.R = radioactive remain, P.E = parent element, b = Time, n = half life.
Where P.E = 100 g , b = 5.55 days, n = 3.823 days.
∴ R.R = 100/
R.R = 100/
R.R = 100/2.73
R.R = 36.63 g.
The mass of radon that decompose = Initial mass of radon - Remaining mass of radon after radioactivity.
Mass of radon that decompose = 100 - 36.63
= 63.37 ≈ 63.4 g
The mass of radon that decompose = 63. 4 g
Explanation:
It is known that charge on xenon nucleus is equal to +54e. And, charge on the proton is
equal to +e. So, radius of the nucleus is as follows.
r =
= 3.0 fm
Let us assume that nucleus is a point charge. Hence, the distance between proton and nucleus will be as follows.
d = r + 2.5
= (3.0 + 2.5) fm
= 5.5 fm
= (as 1 fm =
)
Therefore, electrostatic repulsive force on proton is calculated as follows.
F =
Putting the given values into the above formula as follows.
F =
=
=
= 411.2 N
or, = N
Thus, we ca conclude that N is the electric force on a proton 2.5 fm from the surface of the nucleus.