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rusak2 [61]
3 years ago
8

An object on top of a building has a GPE of 23,048j and a mass of 39kg, What is the height of the object

Chemistry
1 answer:
kirill115 [55]3 years ago
3 0

Answer:

<h2>59.1 m</h2>

Explanation:

The height of the object can be found by using the formula

h =  \frac{p}{mg }  \\

where

p is the potential energy

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

h =  \frac{23048}{39 \times 10}  =  \frac{23048}{390}  \\  = 59.0974...

We have the final answer as

<h3>59.1 m</h3>

Hope this helps you

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Calculate the rate constant at 200.°C for a reaction that has a rate constant of 8.30 × 10−4 s−1 at 90.°C and an activation ener
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Answer:

23.0 s⁻¹ is rate constant

Explanation:

Using the Arrhenius equation:

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Where k is rate constant

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And T is absolute temperature (24°C + 273 = 297K)

Replacing:

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Explanation:

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