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ololo11 [35]
3 years ago
9

How are the carbon, oxygen, and nitrogen cycles vital to sustaining life on Earth?. a.. Carbon, oxygen, and nitrogen are vital c

omponents of life on Earth.. b.. The carbon, oxygen, and nitrogen cycles allow vital elements to return to usable form by organisms.. c.. The carbon, oxygen, and nitrogen cycles are an important interface between biotic and abiotic factors.. d.. All of the above are reasons the carbon, oxygen, and nitrogen cycles are vital to life on Earth
Chemistry
2 answers:
kumpel [21]3 years ago
5 0

The correct answer is (D)


All the above are reasons the carbon , oxygen, and nitrogen cycles are vital to life on earth.


The explanation:


because :


1) Carbon, oxygen, and nitrogen are vital components of life on Earth.


2) The carbon, oxygen, and nitrogen cycles allow vital elements to return to usable form by organisms.


3)The carbon, oxygen, and nitrogen cycles are an important interface between biotic and abiotic factors


4) They are all biogeochemical cycles.


5) They all involve an interaction between living and nonliving elements.

6)They are all part of the Earth system.

Llana [10]3 years ago
4 0
The correct answer among the choices listed is option D. Carbon, oxygen, and nitrogen cycles vital to sustaining life on Earth because they are vital components of life, vital elements to return to usable form by organisms and an important interface between biotic and abiotic factors.
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Answer:

Oxide of M is M_2O_3 and sulfate of M_2(SO_4)_3

Explanation:

0.303 L of molecular hydrogen gas measured at 17°C and 741 mmHg.

Let moles of hydrogen gas be n.

Temperature of the gas ,T= 17°C =290 K

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Using an ideal gas equation:

PV=nRT

n=\frac{PV}{RT}=\frac{0.9633 atm\times 0.303 L}{0.0821 atm L/mol K\times 290 K}=0.01225 mol

Moles of hydrogen gas produced = 0.01225 mol

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Moles of metal =\frac{0.225 g}{27.0 g/mol}=8.3333 mol

So, 8.3333 mol of metal M gives 0.01225 mol of hydrogen gas.

\frac{8.3333}{0.01225 mol}=\frac{2}{x}

x = 2.9 ≈ 3

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Formulas for the oxide and sulfate of M will be:

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