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ololo11 [35]
3 years ago
9

How are the carbon, oxygen, and nitrogen cycles vital to sustaining life on Earth?. a.. Carbon, oxygen, and nitrogen are vital c

omponents of life on Earth.. b.. The carbon, oxygen, and nitrogen cycles allow vital elements to return to usable form by organisms.. c.. The carbon, oxygen, and nitrogen cycles are an important interface between biotic and abiotic factors.. d.. All of the above are reasons the carbon, oxygen, and nitrogen cycles are vital to life on Earth
Chemistry
2 answers:
kumpel [21]3 years ago
5 0

The correct answer is (D)


All the above are reasons the carbon , oxygen, and nitrogen cycles are vital to life on earth.


The explanation:


because :


1) Carbon, oxygen, and nitrogen are vital components of life on Earth.


2) The carbon, oxygen, and nitrogen cycles allow vital elements to return to usable form by organisms.


3)The carbon, oxygen, and nitrogen cycles are an important interface between biotic and abiotic factors


4) They are all biogeochemical cycles.


5) They all involve an interaction between living and nonliving elements.

6)They are all part of the Earth system.

Llana [10]3 years ago
4 0
The correct answer among the choices listed is option D. Carbon, oxygen, and nitrogen cycles vital to sustaining life on Earth because they are vital components of life, vital elements to return to usable form by organisms and an important interface between biotic and abiotic factors.
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At 25 °C, what is the hydroxide ion concentration, [OH−] , in an aqueous solution with a hydrogen ion concentration of [H+]=4.8×
algol [13]

[OH⁻]= 1 x 10⁻¹⁴ : 4.8 x 10⁻⁴ = 2.083 x 10⁻¹¹

3 0
1 year ago
Enter your answer in the provided box.
Lina20 [59]

Answer:

5.06atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1.34 atm

P2 = ?

V1 = 5.48 L

V2 = 1.32 L

T1 = 61 °C = 61 + 273 = 334K

T2 = 31 °C = 31 + 273 = 304K

Using P1V1/T1 = P2V2/T2

1.34 × 5.48/334 = P2 × 1.32/304

7.34/334 = 1.32P2/304

Cross multiply

334 × 1.32P2 = 304 × 7.34

440.88P2 = 2231.36

P2 = 2231.36/440.88

P2 = 5.06

The final pressure is 5.06atm

6 0
3 years ago
Butanol is composed of carbon, hydrogen, and oxygen. If 1.0 mol of butanol contains 6.0 x 1024 atoms of hydrogen, what is the su
yanalaym [24]

Answer:

Option B. 10

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If 1 mol of butanol contains 6×10²⁴ atoms of H, let's calculate the amount of H.

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H, has 10 moles in the butano formula.

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Gnom [1K]
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