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telo118 [61]
3 years ago
12

Balance the following equation Sb2S3+O3=Sb2O3+SO2

Chemistry
1 answer:
Alexeev081 [22]3 years ago
8 0

Answer:

Sb2S3+2O3=Sb2O3+S3O2

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The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.
Alona [7]

Answer:

a. 52.8

Explanation:

To find the number of moles of HCl we use the relation M₁V₁=M₂V₂

where M₁ is the initial molarity, M₂ the new molarity, V₁ the initial volume used, and V₂ the final volume obtained.

M₁=7.91 M

M₂=2.13 M

V₁=?

V₂=196.1 mL

Replacing these values in the relationship.

M₁V₁=M₂V₂

7.91 M× V₁=2.13 M×196.1 mL

V₁=(2.13 M×196.1 mL)/7.91 M

=52.8 mL

3 0
3 years ago
A student was titrating the calcium and water solution and notice the formation of bubbles in the flask. which description would
labwork [276]
Hi!

When titrating Calcium and Water solution, if there is some CaCO3 in the solution, the following reactions may occur in acid solution:

CaCO₃ + H⁺ → Ca⁺² + HCO₃⁻

HCO₃⁻ + H⁺ ↔ H₂CO₃ → CO₂ (g) + H₂O

The bubbles are from CO₂ that is being developed from an acidic solution of CaCO₃

4 0
3 years ago
A 1.42-g sample of a pure compound with formula m2so4 was dissolved in water and treated with an ex- cess of aqueous calcium chl
solong [7]

The reaction between m_{2}SO_{4} with calcium chloride can be shown as-m_{2}SO_{4}+CaCl_{2}→CaSO_{4}↓+2mCl. The molecular weight of CaSO_{4} is 136.14g. The weight of sulfate ion is 96.06g. The molecular weight of m_{2}SO_{4} = (2×m + 96.06). From the reaction we can see that 1 mole of calcium chloride reacts with 1 molesm_{2}SO_{4} to produce 1 mole of calcium sulfate. Now 1.36g of calcium sulfate is equivalent to 1.36/136.14=9.989×10^{-3} moles of calcium sulfate.

Thus, 9.989×10^{-3} moles of m_{2}SO_{4} reacts in this reaction.

Let assume the atomic mass of m is x thus the molecular weight of m_{2}SO_{4} is 2x+96.

So we may write 9.989×10^{-3}× (2x+96) =1.42

Or, 2x + 96 = 142.146

Or, 2x = 46.146

Or, x = 23.073

Thus the atomic mass of m is 23.073. The atom (m) is sodium (Na).  

8 0
3 years ago
What is the molar mass of HCl??
irakobra [83]
HCl = 1 + 35.5 => 36.5 g/mol

hope this helps!
7 0
3 years ago
How much of a 50g sample of 85Kr will remain after 2 half-lives?
Rashid [163]

Answer:

i need help with my work

Explanation:

8 0
2 years ago
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