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2 years ago

Find the equation of the line with slope = -5 and passing through (4,-17). write your equation in the form y = m x + b y=mx+b.

2 answers:

5 0

Y=mx+c
m= -5

Just substitute the values of the point into the equation to find c

-17=-5 x 4 +b
-70+20+b
3=b

y=-5x+3

Hope I helped :)

Andru [333]2 years ago

4 0

Y = -5x + b

-17 = -5(4) + b

-17 = -20 + b
+20 +20

3 = b

y = -5x + 3

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Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Select three options.

MakcuM [25]

Answer:

8(x2 + 2x) = –3

8(x2 + 2x + 1) = –3 + 8

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

Step-by-step explanation:

Solving Quadratic Equations

Sometimes it's preferred to solve quadratic equations without the use of the known quadratic formula solver. One of the most-used methods consists of completing squares and solving for x.

We have the equation

$\displaystyle 8x^2+16x+3=0$

We separate variables from constants

$\displaystyle 8x^2+16x=-3$

Taking the common factor 8

$\displaystyle 8(x^2+2x)=-3$

Completing squares in the brackets and balancing the equation in the right side

$\displaystyle 8(x^2+2x+1)=-3+8$

Factoring the perfect square

$\displaystyle 8(x+1)^2=5$

Isolating x

$\displaystyle (x+1)^2=\frac{5}{8}$

$\displaystyle (x+1)=\pm \sqrt{\frac{5}{8}}$

$\displaystyle x=-1\pm \sqrt{\frac{5}{8}}$

We can clearly see the steps used to solve the quadratic equation are (in order and written like in the question)

8(x2 + 2x) = –3

8(x2 + 2x + 1) = –3 + 8

x = –1 Plus or minus StartRoot StartFraction 5 Over 8 EndFraction EndRoot

7 0

2 years ago

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Jack crawled 4 ft and Christine crawled 3⁄4 the distance Jack crawled. If you add the distance they each crawled together, what

stepan [7]

Before going into the details of the problem, let us first write down the most important information required for solving this problem.
1 ft = 12 inches
The distance that was crawled by Jack = 4 ft
      = (4 * 12) inches
      = 48 inches
The distance crawled by Christine = 3/4 of the distance crawled by Jack
   = (3/4) * 48 inches
   = 3 * 12 inches
   = 36 inches
Then
The total distance crawled by the two children's = (48 + 36) inches
   = 84 inches
So Jack and Christine together crawled a distance of 84 inches.

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