Answer: ![\dfrac{7}{8}](https://tex.z-dn.net/?f=%5Cdfrac%7B7%7D%7B8%7D)
Step-by-step explanation:
Given : When a coin is tossed twice , the total outcomes will become
HHH , HHT , HTH , THH , TTH , THT , HTT ,TTT
Total outcomes = 8
Favorable outcomes to obtain 1 and 3 inclusive = HHT , HTH , THH , TTH , THT , HTT ,TTT
Number of favorable outcomes = 7
Probability that the number of tails obtained will be between 1 and 3 inclusive = ![\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7BFavorable%20outcomes%7D%7D%7B%5Ctext%7BTotal%20outcomes%7D%7D)
![=\dfrac{7}{8}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B7%7D%7B8%7D)
Hence, the probability that the number of tails obtained will be between 1 and 3 inclusive ![=\dfrac{7}{8}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B7%7D%7B8%7D)