Answer:
Given that an article suggests
that a Poisson process can be used to represent the occurrence of
structural loads over time. Suppose the mean time between occurrences of
loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a
4-year period? c). How long must a time period be so that the probability of no loads
occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a
4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads
occurring during that period is at most 0.3 is given by: 3.3 years
Step-by-step explanation:
Answer:
v=2
Step-by-step explanation:
5v=10
v=2
64/1 or 64 heartbeats in 1 minute
Answer:
A - y = 1200(1+.05)^30
Step-by-step explanation:
In this case, you need to calculate the future value and the formula to calculate that is:
FV=PV*(1+r)^n
FV=future value
PV=present value
r=rate
n=number of periods of time
The present value would be the price of the ring which is $1200. The rate is 5% per year and the number of periods of time is 30 years since you need to find the ring's worth in 30 years. Now, you can replace the values on the formula:
FV=1200*(1+0.05)^30
According to this, the answer is that the equation to calculate how much will it be worth in 30 years is: y = 1200(1+.05)^30.
