1) Jason: Shop A - 11 units; Shop B - 12 units. Sales increase at 17% per week. So, 11 + 12 = 23.
f(x) = 23(1.17)ˣ
2) Daniel: Element A temp - 44(1.13)ˣ ; Element B temp - 17(1.13)ˣ. How much temp of Element A be more than the temp of Element B.
f(x) = 44(1.13)ˣ - 17(1.13)ˣ = 27(1.13)ˣ
f(x) = 27(1.13)ˣ
3) Maggie: Tshirt price - $13. Charity donation - 270
f(x) = 13x - 270
4) Mr. Smith: Length of backyard - 30x + 29 ; Length of square patio - 13x + 6
Length not covered by the patio.
f(x) = (30x + 29) - (13x + 6) = 30x - 13x + 29 - 6 = 17x + 23
f(x) = 17x + 23
Answer: 6,000.
Step-by-step explanation:
Consider, please, this solution/explanation:
1. suppose, that number of cars is 'x', numbers of buses is 'y'.
2. according to the condition 'a total of 32', it means that x+y=32. This is the 1st equation.
3. according to the condition in one car are 3x persons, in one bus are 27y persons, and totaly 3x+27y=408 people. This is the 2d equation.
4. if to solve the system of two equations:
Answer: 13 - b., 19 - c.
Answer:
7x + 2y = -22
Step-by-step explanation:
Standard form looks like Ax + By = C.
Start with Y = -7/2x-11. Better to write that as Y = (-7/2)x - 11 to emphasize that the coefficient of x is the fraction -7/2.
Move the (-7/2)x term to the left:
(7/2)x + y = -11
Multiply all terms by 2 to eliminate the fractions:
7x + 2y = -22 (answer)
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
