Answer: b) Less dense
Explanation:
Differences in density is one reason objects float or sink.
An object more dense than the fluid in which it is immersed will sink, while objects less dense than the fluid in which it is immersed will float to the surface.
But objects floats at constant level if the density is equal to the density of the fluid in which it is immersed; it neither rises nor sinks in the fluid in this case.
Answer:
The correct answer is - directly; Avogadro’s.
Explanation:
At the same temperature and pressure, gases of the same or equal volume have the same number of molecules. The relation between the moles of the gases and the volume of the gases are indirectly proportional to one another at the same temperature and pressure. This law is called Avogadro's law. In the case of an ideal gas of a particular mass has the volume and moles are directly proportional.
Thus, the correct answer is - directly; Avogadro’s.
Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.
Explanation : Given,
Mass of oxygen in sulfur dioxide = 3.49 g
Mass of sulfur in sulfur dioxide = 3.50 g
Mass of oxygen in sulfur trioxide = 9.00 g
Mass of sulfur in sulfur trioxide = 6.00 g
Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.
Mass of oxygen per gram of sulfur for sulfur dioxide = 
Mass of oxygen per gram of sulfur for sulfur dioxide = 
and,
Mass of oxygen per gram of sulfur for sulfur trioxide = 
Mass of oxygen per gram of sulfur for sulfur trioxide = 
Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.
In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.
<h3>What is molarity?</h3>
Molarity (M) is a unit of concentration of solutions, and it is defined as the moles of a solute per liters of a solution.
- Step 1: Calculate the liters of solution required.
A chemist has a 3.00 M KBr solution and wants to measure 0.733 moles of KBr. The required volume is:
0.733 mol × (1 L/3.00 mol) = 0.244 L
- Step 2: Convert 0.244 L to mL.
We will use the conversion factor 1 L = 1000 mL.
0.244 L × (1000 mL/1 L) = 244 mL
In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.
Learn more about molarity here: brainly.com/question/9118107
Answer:
4 moles of Na are needed.