Gay-Lussacs law states that pressure is directly proportional to temperature at constant volume.
in this case the volumes of the 2 containers remain the same therefore volume is constant.
P/ T = k
where P - pressure, T - temperature and k - constant
when temperature decreases the pressure too decreases and vice versa.
if temperature of one container is lowered the pressure also reduces.
since one containers temperature is lowered the pressure in that container reduces.
answer is when temperature is lowered, pressure too is lowered.
The molecular weight of unknown gas : 23.46 g/mol
<h3>Further explanation</h3>
Given
A vessel contains 10% of oxygen and 90% of an unknown gas.
diffuses rate of mixed gas = 86 s
diffuses rate of O₂ = 75 s
Required
the molecular weight of unknown gas (M)
Solution
The molecular weight of mixed gas :(M O₂=32 g/mol)
Graham's Law :
3.
∆E = ∆m x c ² ∆m = E / c ² ∆m = 3,83•10^-12 / 3•10^8 ² ∆m = 4,256•10^-29 kg
Taking this class as well
The structure is known as the nucleus
