Answer:
C
Explanation:
A nuclear reaction is one in which 2 atoms combine or an atom divides to give rise to entirely different atoms. This is basically the difference it has with a chemical reaction. In a chemical reaction, only new compounds are formed but not new elements. In the case of a nuclear reaction however, even if new elements are not formed, a different atom would be formed.
Compound B will be propene as a result of an elimination reaction involving potassium tert-butoxide and an alkyl halide. In proton NMR, alkenes exhibit signals in the 5–6 ppm range.
<h3>What are Elimination Reactions?</h3>
Elimination reactions are one sort of reaction that are mostly utilized to convert saturated compounds (organic molecules that contain single carbon-carbon bonds) to unsaturated compounds (compounds that feature double or triple carbon-carbon bonds). Additionally, it plays a significant role in the production of alkenes.
The elimination response is composed of the following three major events:
- Proton exclusion.
- The synthesis of a C-C pi bond.
- As a result, the relationship between the departing group's members has grown increasingly distant.
To learn more about Elimination reactions visit:
brainly.com/question/14693649
#SPJ4
We are asked to convert the value <span>72 kilometers per hour to units of meters per second. We need conversion factors to multiply to this value. We convert as follows:
</span><span>72 km / hr ( 1000 m / 1 km ) ( 1 hr / 3600 s ) = 20 m/s --->OPTION B</span><span>
</span>
Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,
C + O2 ------> CO2
Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2.
<u> 86.5 g CO </u> = 1.966 moles CO2
44 g CO2/ mole
Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel.
1.966 moles CO2 x <u> 1 mole C </u> x <u> </u><u>12 g C </u> = 23.59 g C
1 mole CO2 1 mole C
We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams.
25.0 g - 23.59 g = 1.41 grams Hydrogen
To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen.
To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel,
Carbon: <u> 1.966 mol </u> = 1.408 x 5 (factor) = 7
1.396 mol
Hydrogen: <u> 1.396 mol </u> = 1.00 x 5 (factor) = 5
1.396 mol
Thus, the empirical formula is C7H5
