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Kamila [148]
3 years ago
8

Question 7 (1 point)

Chemistry
2 answers:
Kamila [148]3 years ago
6 0
1.Organism
2.Organ system
3.Organs
4.Tissues
5.Cell
VikaD [51]3 years ago
6 0
Cell,tissue,organisms,organ system
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Enough of a monoprotic acid is dissolved in water to produce a 1.64 M solution. The pH of the resulting solution is 2.82 . Calcu
Lady bird [3.3K]

Answer:

Ka = 1.39x10⁻⁶

Explanation:

A monoprotic acid, HX, will be in equilibrium in an aqueous medium such as:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

<em>Where Ka is:</em>

Ka = [H⁺] [X⁻] / [HX]

<em>Where [] is the molar concentration in equilibrium of each specie. </em>

The equilibrium is reached when some HX reacts producing H+ and X-, that is:

[HX] = 1.64M - X

[H⁺] = X

[X⁻] = X

As pH is 2.82 = -log [H⁺]:

[H⁺] = 1.51x10⁻³M:

[HX] = 1.64M - 1.51x10⁻³M = 1.638M

[H⁺] = 1.51x10⁻³M

[X⁻] = 1.51x10⁻³M

And Ka is:

Ka = [1.51x10⁻³M] [1.51x10⁻³M] / [1.638M]

<h3>Ka = 1.39x10⁻⁶</h3>
6 0
3 years ago
PLEASE HELP:<br><br> iron reacts with nitrogen to form iron(III) nitride
lutik1710 [3]

Answer:

2Fe +N_{2} -> 2FeN

Explanation:

Iron is Fe, nitrogen is N. Nitrogen is diatomic, which means it occurs as a molecular pair by itself. Iron III nitride has a chemical formula of FeN because nitrogen has a charge of 3-, and iron III tells us the iron has a charge of 3+ so you just need one of each to make the charges balance and the compound neutral.

3 0
2 years ago
Find the density of a material, given that a 5.01 g sample occupies 3.46 mL
Alex73 [517]

Answer:

The answer is

<h2>1.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of material = 5.01 g

volume = 3.46 mL

The density of the material is

density =  \frac{5.01}{3.46}  \\  = 1.44797687...

We have the final answer as

<h3>1.45 g/mL</h3>

Hope this helps you

3 0
3 years ago
Which is the molar mass of H2O?
Svetllana [295]
H=(2x1.008)=2.016
O= 15.999

15.999
+ 2.016
______
18.015 g/mol :)

3 0
2 years ago
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I think its the sea cucumber and sea urchin

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