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3 years ago

Question 7 (1 point)

Chemistry

2 answers:

Kamila [148]3 years ago

6 0

1.Organism
2.Organ system
3.Organs
4.Tissues
5.Cell

VikaD [51]3 years ago

6 0

Cell,tissue,organisms,organ system

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A sample of an unknown gas effuses in 11.1 min. An equal volume of H2 in the same apparatus at the same temperature and pressure

Anit [1.1K]

Answer:

Molar mass of the gas is 0.0961 g/mol

Explanation:

The effusion rate of an unknown gas = 11.1 min

rate of $H_{2}$ effusion = 2.42 min

molar mass of hydrogen = 1 x 2 = 2 g/m

molar mas of unknown gas = ?

From Graham's law of diffusion and effusion, the rate of effusion and diffusion is inversely proportional to the square root of its molar mass.

from

$\frac{R_{g} }{R_{h} }$ = $\sqrt{\frac{M_{h} }{M_{g} } }$

where

$R_{h}$ = rate of effusion of hydrogen gas

$R_{g}$ = rate of effusion of unknown gas

$M_{h}$ = molar mass of H2 gas

$M_{g}$ = molar mass of unknown gas

substituting values, we have

$\frac{11.1 }{2.42 }$ = $\sqrt{\frac{2 }{M_{g} } }$

4.587 = $\sqrt{\frac{2 }{M_{g} } }$

$\sqrt{M_{g} }$ = $\sqrt{2}$ /4.587

$\sqrt{M_{g} }$ = 0.31

$M_{g}$ = $0.31^{2}$ = 0.0961 g/mol

7 0

2 years ago

How many grams of potassium chloride are in 4.25 x 1023 molecules?

liubo4ka [24]

Answer:

Nintendo Co., Ltd. is a Japanese multinational consumer electronics and video game company headquartered in Kyoto. The company was founded in 1889 as Nintendo Karuta by craftsman Fusajiro Yamauchi and originally produced handmade hanafuda playing cards

Explanation:

6 0

3 years ago

The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the signs of ΔH, ΔS, a

Nostrana [21]

The question is incomplete, the complete question is;

The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the signs of ∆H, ∆S, and ∆G for the boiling process at this temperature.

A. ∆H > 0, ∆S > 0, ∆G < 0

B. ∆H > 0, ∆S > 0, ∆G > 0

C. ∆H > 0, ∆S < 0, ∆G < 0

D. ∆H < 0, ∆S > 0, ∆G > 0

E. ∆H < 0, ∆S < 0, ∆G > 0

Answer:

A. ∆H > 0, ∆S > 0, ∆G < 0

Explanation:

During boiling, a liquid is converted to vapour. This is a phase change for which heat is absorbed because energy must be taken in to break the intermolecular bonds in the liquid before it can be converted to a gas. Hence ∆H>0

Secondly, a phase change from liquid to gas leads to an increase in entropy hence ∆S>0.

Thirdly, the process is spontaneous. For every spontaneous process ∆G<0

3 0

3 years ago

What is the pressure in atm exerted by 1.8 g of H_{2} gas exert in a 4.3 L balloon at 27°C? R =; 0.821(L^ * atm)/(mol^ * K)

trapecia [35]

Answer:

5.12 atm

Explanation:

Before you can use the Ideal Gas Law to find the pressure, you need to convert grams to moles (via molar mass).

Molar Mass (H₂): 2(1.008 g/mol)

Molar Mass (H₂): 2.016 g/mol

1.8 grams H₂ 1 mole
---------------------- x ---------------------- = 0.893 moles H₂
2.016 grams

The Ideal Gas Law equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

After converting Celsius to Kelvin, you can plug the given values into the equation and simplify to find the pressure.

P = ? atm R = 0.0821 L*atm/mol*K

V = 4.3 L T = 27 °C + 273.15 = 300.15 K

n = 0.893 moles

PV = nRT

P(4.3 L) = (0.893 moles)(0.0821 L*atm/mol*K)(300.15 K)

P(4.3 L) = 22.0021

P = 5.12 atm

**Based on my past experiences, I believe the constant (R) you provided may have been mistyped. Instead of 0.821, I used 0.0821.**

6 0

1 year ago

What is the Formula for the volume of an irregular object?

SCORPION-xisa [38]

Answer:

Multiply the length, width, and height together.

( length *, width *, height )

The answer to this is multiplication problem is the volume of the object.

Explanation:

- Do not measure the height of the entire container, just the height from one watermark to another.

I hope this helped!

8 0

3 years ago