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ser-zykov [4K]
3 years ago
10

Help me here in this equation and tell me how to check it to know if solution is the answer

Mathematics
1 answer:
Leokris [45]3 years ago
4 0

ok so first step is to get rid of x

than you want to subtract x from 4/5x

than you want to minus 7 from 9 and you get 2

now times 5 to both sides like like this

4/5x5 and 2x5=

4x=10

x=2.5

i hope this helps you


\frac{4}{5} x \frac{5}{1} = \frac{4}{1} =4x

then you have 2 x 5= 10

so then you will have 4x=10\\10divide by 4 =\\2.5\\x=2.5

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Can anyone help me on 4,7,10<br> Using simplest form
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I will give the answers, you can comment any questions! Glad to help you!!!

4.) 7/8

7.) 9/10

10.)1 1/6

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7 0
3 years ago
I WILL GIVE BRAINIEST!!
Vikki [24]

In order to prove that this quadrilateral is a parallelogram, we need to get the opposite sides to be parallel.

The answer would be D because it shows 2 triangles to be equal. If they are equal then they must have corresponding sides.

5 0
3 years ago
Given: AB || DE , AD bisects BE.<br> Prove: ABC = DEC using the ASA postulate.
Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

\triangle ABC and \triangle DEC.

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.

i.e. AB || ED and \angle B and \angle E are alternate angles \Rightarrow \angle B = \angle E.

2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

\Rightarrow \angle ACB = \angle DCE

Also, it is given that <em>AD bisects BE</em>.

i.e. EC = CB

1. \angle B = \angle E

2. EC = CB

3. \angle ACB = \angle DCE

So, we can in see that in \triangle ABC and \triangle DEC, two angles are equal and side between them is also equal to each other.

Hence, proved that \triangle ABC \cong \triangle DEC.

8 0
3 years ago
Question 1 (1 point)
Naily [24]

Answer:

P ( -1, -3)

Step-by-step explanation:

Given ratio is AP : PB = 3 : 2 = m : n  and points A(5,6) B(-5,-9)

We will calculate coordinates of the point P which divides line segment AB  in the following way:

xp = (n · xa + m · xb) / (m+n) = (2 · 5 + 3 · (-5)) / (3+2) = (10-15) / 5 = -5/5 = -1

xp = -1

yp = (n · ya + m · yb) / (m+n) = (2 · 6 + 3 · (-9)) / (3+2) = (12-27) / 5 = -15/5 = -3

yp = -3  

Point P( -1, -3)

8 0
3 years ago
7+(-14)+(-6)+13+4=-37​
Kaylis [27]

Answer:

4

Step-by-step explanation:

7+(-14)+(-6)+13+4

7+(-20)+13+4

(-13)+13+4

0+4

4

4 0
3 years ago
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