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4.) 7/8
7.) 9/10
10.)1 1/6
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In order to prove that this quadrilateral is a parallelogram, we need to get the opposite sides to be parallel.
The answer would be D because it shows 2 triangles to be equal. If they are equal then they must have corresponding sides.
Answer:
As per ASA postulate, the two triangles are congruent.
Step-by-step explanation:
We are given two triangles:
and
.
AD bisects BE.
AB || DE.
Let us have a look at two properties.
1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.
i.e. AB || ED and
and
are alternate angles
.
2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

Also, it is given that <em>AD bisects BE</em>.
i.e. EC = CB
1. 
2. EC = CB
3. 
So, we can in see that in
and
, two angles are equal and side between them is also equal to each other.
Hence, proved that
.
Answer:
P ( -1, -3)
Step-by-step explanation:
Given ratio is AP : PB = 3 : 2 = m : n and points A(5,6) B(-5,-9)
We will calculate coordinates of the point P which divides line segment AB in the following way:
xp = (n · xa + m · xb) / (m+n) = (2 · 5 + 3 · (-5)) / (3+2) = (10-15) / 5 = -5/5 = -1
xp = -1
yp = (n · ya + m · yb) / (m+n) = (2 · 6 + 3 · (-9)) / (3+2) = (12-27) / 5 = -15/5 = -3
yp = -3
Point P( -1, -3)
Answer:
4
Step-by-step explanation:
7+(-14)+(-6)+13+4
7+(-20)+13+4
(-13)+13+4
0+4
4