The intercepts of the given equations is as given in the task content is; Choice B; (15,0,0),(0,10,0) ,(0,0,5).
<h3>What are the intercepts of the equation as give in the task content?</h3>
The x-intercept of the given equation can be determined by setting values of y and z to zero.
The y-intercept can be determined by setting x and z to zero.
While the z-intercept can be determined by setting x and y to zero.
Consequently, the X-intercept of the given equations is; 2x +3(0) = 30; x = 15.
Therefore, we have; (15,0,0)
The y-intercept is therefore; 2(0) +3y = 30; 3y = 30; y = 30/3 = 10 and. we have; (0,15,0)
And hence, the z-intercept is; z = 30/6 = 5.
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Answer:
x = 9
Step-by-step explanation:
Answer:
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Step-by-step explanation:
yadda yadda yadda that is the answer
Answer:
Equation of line passing through point A = ( 19 , 3 ) , and point B = ( 20 , 3 ) is
y−3=0
OR
Equation of line passing through point A = ( 19 , 3 ) , and point B = ( 29 , 3 ) is
y=0x+3
Answer:

Step-by-step explanation:
Given
sinΘ =
= 
Then the hypotenuse = 5 and one leg of the right triangle is 3
Using Pythagoras' identity to find the second leg (x)
x² + 3² = 5²
x² + 9 = 25 ( subtract 9 from both sides )
x² = 16 ⇒ x = 4
cosΘ =
= 