Answer:
(x - 8)(2x + 3)
Step-by-step explanation:
To factor a polynomial of the form
ax² + bx + c,
follow these steps:
1) Multiply ac together.
2) Find 2 factors of ac that add to b. Call these factors p and q.
3) Break up the middle term of the polynomial into px + qx.
4) Factor by grouping.
Now let's follow the steps above with your problem.
You are given the polynomial
2x² - 13x - 24,
so a = 2, b = -13, and c = -24
1) Find ac.ac is the product 2(-24) = -48
2) Now we need to find 2 factors of -48 that add to b, -13.
I know that 48 = 3 × 16, so if we use -16 and 3 for the two numbers, we have
-16 + 3 = -13
and -16 × 3 = -48.
3) Now we break up the middle term of the polynomial, -13x, into -16x + 3x.
The polynomial is now
2x² - 16x + 3x - 24
4) We factor the polynomial by grouping. To factor by grouping, you factor a common factor out of the first 2 terms and factor out a common factor out of the last two terms.
2x² - 16x + 3x - 24 =
= 2x(x - 8) + 3(x - 8)
We now see the common factor of x - 8, so we factor that out.
= (x - 8)(2x + 3)
Answer: (x - 8)(2x + 3)
Answer:
w= -52
Step-by-step explanation:
We simplify the equation to the form, which is simple to understand
15-w/4=28
Simplifying:
15-0.25w=28
We move all terms containing w to the left and all other terms to the right.
-0.25w=+28-15
We simplify left and right side of the equation.
-0.25w=+13
We divide both sides of the equation by -0.25 to get w.
w= -52
Hope it Helps :) !!
First we will find the value of x.
To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.
We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.
angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24
Now we can use 24 for x and find the value of angle QRO
angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67
So the answer choice B is the right answer.
Hope this helps :)<span />
f(x)= 3x³ - 18x +9
Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.
Identity I: (a + b)² = a² + 2ab + b²
Identity II: (a – b)² = a² – 2ab + b²
Identity III: a² – b²= (a + b)(a – b)
Identity IV: (x + a)(x + b) = x² + (a + b) x + ab
Identity V: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
Identity VI: (a + b)³ = a³ + b³ + 3ab (a + b)
Identity VII: (a – b)³ = a³ – b³ – 3ab (a – b)
Identity VIII: a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)
f(x) = (3x + 6) (x - 3)²
= ( 3x + 6) ( x - 3 )²
= ( 3x + 6)( x² - 6x + 9)
= 3x( x² - 6x + 9) + 6( x² - 6x + 9)
= 3x³ - 6x² + 18x + 6x² - 36x +9
= 3x³ - 18x +9
To learn more about algebraic expansions, refer to brainly.com/question/4344214
#SPJ9
Answer:
ANSWER IS C,,, 0
Step-by-step explanation:
the J+8 is basically going along with that the answer J+8 could be LESS than or equal to 8 if we pick any other number its going to be GREATER than 8 an we want LESS than 8,,,hope this helps.
