Given 3.72 g of P and 21.28g of Cl, converting these to moles: ( 3.72 g P)(mol P/30.97 g P) = 0.12 mol P (21.28 g Cl)(mol Cl/35.45 g Cl) = 0.60 mol Cl P:Cl = 0.12/0.60, therefore P: Cl =1/5 Therefore, PCl5 hope it helps
The balanced equation is as below
Na2CO3 +2 HCl → 2 NaCl +H2O + CO2
<u><em>Explanation</em></u>
step 1 : write the unbalanced chemical equation
that is Na2CO3 + HCl→ NaCl + H2O +CO2
Step 2: change the coefficient ( <em>number in front of chemical formula) </em>to make sure the number of atoms of an element are the same in both side.
By adding 2 in front of HCl and in front of NaCl balance the equation.
Therefore the balanced equation is as below
Na2CO3 +2HCl → 2NaCl +H2O +Co2
Answer:
1.46 moles NaCl
Explanation:
To find the moles of NaCl, you need to multiply the given value (0.731 moles BaCl₂) by the mole-to-mole ratio of the two relevant molecules. This ratio is made up of the coefficients in the balanced reaction. The numerator should contain moles NaCl to allow for the cancellation of moles BaCl₂. The final answer should have 3 sig figs to reflect the given value.
1 BaCl₂(aq) + Na₂SO₄(aq) ---> BaSO₄(s) + 2 NaCl(aq)
0.731 mole BaCl₂ 2 moles NaCl
--------------------------- x ------------------------- = 1.46 moles NaCl
1 mole BaCl₂