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3 years ago

Consider the three statements below. Which numbered response contains all the statements that are true and no false statements?

Chemistry

1 answer:

vladimir1956 [14]3 years ago

6 0

Answer:

a) I, II, and III

Explanation:

For the first statement;

Solvation, is the process of attraction and association of molecules of a solvent with molecules or ions of a solute. if the solvent is water, we call this process hydration.

This means the statement is TRUE.

For the second statement;

The negatively-charged side of the water molecules are attracted to positively-charged ions. In the case of water, the oxygen end is the negatively charged side of water. This means the statement is TRUE.

For the third statement;

The positively-charged side of the water molecules are attracted to the negatively-charged chloride ions. In the case of water, the hydrogen end is the positively charged side of water. This means the statement is TRUE.

Going through the options, we can tell that the correct option is option A.

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A carbon nanoparticle (very small particle) contains 8000 carbon atoms. According to the Einstein model of a solid, how many osc

Rudiy27

Answer:

24000

Explanation:

Given that:

The numbers of carbon atoms = 8000

According to the Einstein model of solid;

Einstein’s model assumes that each atom of the solid vibrates around its position of equilibrium independently of the other atoms (which amounts to neglecting the interactions between particles.

Number of oscillators = 3(8000)

Number of oscillators = 24000

5 0

3 years ago

What mass of Al2(SO4)3 results from mixing 12.93 g of AlCl3 with 10.34 g of (NH4)2SO3 as shown with a 54.2% yield?

avanturin [10]

Mass of Al₂(SO₄)₃ : 4.822 g

<h3>Further explanation </h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

2AlCl₃ + 3(NH₄)₂SO₄⇒Al₂(SO₄)₃+ 6NH₄Cl

MW AlCl₃ :133,34 g/mol

MW (NH₄)₂SO₄ : 132,14 g/mol

MW Al₂(SO₄)₃ : 342,15 g/mol

mol AlCl₃

$\tt mol=\dfrac{12.93}{133.34}=0.097$

mol (NH₄)₂SO₄

$\tt mol=\dfrac{10.34}{132.14}=0.078$

Limitng reactants (ratio mol : coefficient = the smaller)

AlCl₃ : (NH₄)₂SO₄ =

$\tt \dfrac{0.097}{2}:\dfrac{0.078}{3}=0.0485:0.026$

(NH₄)₂SO₄ ⇒ limiting reactants

So mol Al₂(SO₄)₃ from (NH₄)₂SO₄

$\tt \dfrac{1}{3}\times 0.078=0.026$

mass Al₂(SO₄)₃

$\tt 0.026\times 342.15=8.896$

with 54.2% yield, the mass of Al₂(SO₄)₃

$\tt 0.542\times 8.896=4.822~g$

7 0

3 years ago

What is the maximum number of grams of copper that could be produced by the reaction of 30.0 of copper oxide with excess methane

Solnce55 [7]

Answer: 24.13 g Cu

Explanation:

<u>Given for this question:</u>

M of CuO = 30 g

m of CuO = 79.5 g/mol

Number of moles of CuO = (given mass ÷ molar mass) = (30 ÷ 79.5) mol

= 0.38 mol

The max number of CuO (s) that can be produced by the reaction of excess methane can be solved with this reaction:

CuO(s) + CH4(l) ------> H2O(l) + Cu(s) + CO2(g)

The balanced equation can be obtained by placing coefficients as needed and making sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side

4CuO(s) + CH4(l) ----> 2H2O(l) + 4Cu(s) + CO2(g)

From the stoichiometry of the balanced equation:

4 moles of CuO gives 4 moles of Cu

1 mole of CuO gives 1 mol of Cu

0.38 mol of CuO gives 0.38 mol of Cu

Therefore, the grams of Cu that can be produced = 0.38 × molar mass of Cu

= 0.38 × 63.5 g

= 24.13 grams

Therefore, 24.13 grams of copper could be produced by the reaction of 30.0 of copper oxide with excess methane

4 0

2 years ago

) A children’s liquid cold medicine has a density of 1.23 g/mL. If a child is to take 2.5 tsp in a dose, what is the mass in gra