Answer:
The rocks of higher density inter the mantle. Due to density they sink and melt. When they melt the density decreases and rises to the top. They then are recycled through volcanoes.
Explanation:
Answer:
D) HCOOCH2CH3
Explanation:
An isomer of a compound is defined as a chemical substances with the same formula (That is, same atoms) but in different structures.
For propanoic acid, there are <em>3 atoms of C, 6 atoms of H and 2 atoms of oxygen.</em>
A) CH2CHCOOH
. Here you have 3 atoms of C but 4 atoms of H. That means this compound is not an isomer.
B) CH3CH2CH2COOH
. Here, there are 4 atoms of C. Thus, is not an isomer.
C) CH3CH(OH)CH2OH. This structure has 3 atoms of C, but 8 atoms of H. Thus, is not an isomer.
D) HCOOCH2CH3. Here, there are 3 atoms of C, 6 atoms of H and 2 atoms of O. Thus, this structure <em>is an isomer of propanoic acid.</em>
Answer:
IR provides structural information about a molecule. TLC and melting point analysis do not provide structural information.
Explanation:
IR gives information about the functional groups present in a molecule. The vibrational frequency of each functional group gives information about the structure of the entire molecule.
Structural features of a molecule are deduced by matching the vibrational frequencies of groups obtained from the IR spectroscopy with that of known functional groups in literature.
Melting point is a qualitative method that can only yield information about the identity of a compound and not its structure. Each compound has its unique melting point recorded in literature and any pure sample of the same compound must have the same sharp meting point.
Thin-layer chromatography (TLC) is a chromatography technique used to separate non-volatile mixtures. After separating the components of the mixture, it does not give any information regarding the identity or the structure of the components of the mixture.
Therefore, only IR yields structural information about a sample.
Answer:
Oil- Only London Dispersion Forces (the weakest intermolecular force)
Water- London Dispersion, Dipole-Dipole, and Hydrogen Bonding
Answer:
See explanation
Explanation:
For the first question, we can see that the pressure is constant so we apply Charles law;
V1/T1 =V2/T2
V1T2 = V2T1
V1= 4.5 L
T1= 27 + 273 = 300 K
V2= ?
T2= 127 + 273 = 400 K
V2= V1T2/T1
V2= 4.5 × 400/300
V2= 6L
For question 2, Charles law is also used;
V1/T1 =V2/T2
V1T2 = V2T1
T1= 338 K
V1= 0.480 L
T2= ?
V2= 9.2 L
T2= V2T1/V1
T2= 9.2 × 338/0.480
T2= 6478.3 K
