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Alexeev081 [22]
3 years ago
15

Definition for starch in science ?

Chemistry
1 answer:
Akimi4 [234]3 years ago
5 0

Answer:

  1. Starch is a polysaccharide comprising glucose monomers joined in α 1,4 linkages. or
  2. Starch is a long-chain polymer of glucose molecules joined together. or
  3. A starch is a complex polysaccharide made up of a large number of glucose units joined together by glycosidic bonds.

Explanation:

starch, a white, granular, organic chemical that is produced by all green plants. Starch is a soft, white, tasteless powder that is insoluble in cold water, alcohol, or other solvents.

Starch is amongst the most abundant plant products and is a mixture of two polymers, amylose and amylopectin. During food processing starch is transformed by hydrothermal treatments. ... The structure of starch is also influenced by specific and non-specific interactions with other food constituents and ingredients.

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"Which statement is true about the removal of a terminal phosphate" from ATP? Choose one: A. The reaction is associated with a p
Mamont248 [21]

Answer:

C. The reaction is energetically favorable.

Explanation:

The reaction which shows the removal of the terminal phosphate from the ATP is shown below:

ATP+H_2O\rightarrow ADP+P_i+\ energy

The Gibbs' free energy change of this reaction, \Delta G^0=-7.3\ kcal/mol

Hence, Option A is not correct.

It is a type of hydrolysis reaction in which water is being added to the molecule.

Hence, Option B is not correct.

The Gibbs' free energy change is negative which means that the reaction is energetically favorable.

Option C is correct.

6 0
4 years ago
The number of protons in an atom is known as its .......... ...........?​
Tanzania [10]

Answer:

Atomic number

Explanation:

Atomic number is the number of protons, and therefore also the total positive charge, in the atomic nucleus. The Rutherford–Bohr model of the hydrogen atom (Z = 1) or a hydrogen-like ion (Z > 1).

7 0
3 years ago
Determine the density of a substance having a mass of 57.2 g and a volume of 33.8mL
TEA [102]
Hey there!:

density = mass / volume

d =  57.2 / 33.8

d = 1.692 g/mL

hope this helps!
7 0
3 years ago
what is meant by a calibration curve for a colored substance being studied with a spectrophotometer? How is a calibration curve
BlackZzzverrR [31]

Answer:

The concentration of the analyte is determined by fitting the absorbance or transmittance obtained by spectrophotometric analysis of the unknown solution into the calibration curve.

Explanation:

In a calibration curve, the instrumental response (absorbance or transmittance), is plotted against the concentration of the analyte (the substance to be measured). The analyst is expected to prepare a series of standard solutions of the analyte within a range of solution concentrations close to the expected concentration of analyte in the unknown solution. The method of least squares may be used to determine the best fit of the line, thus, the concentration of the analyte. This method is only used for the determination of the concentration of coloured substances (spectrophotometry).

3 0
3 years ago
You are given a solid that is a mixture of Na2SO4 and K2SO4. A 0.205-g sample of the mixture is dissolved in water. An excess of
Svetach [21]

Answer:

Mass of SO₄⁻² = 0.123 g.

Mass percentage of SO₄⁻² = 41.2%

Mass of Na₂SO₄ = 0.0773 g

Mass of K₂SO₄ = 0.1277 g

Explanation:

Here we have

We place Na₂SO₄ = X and

K₂SO₄ = Y

Therefore

X +Y = 0.205 .........(1)

Therefore since the BaSO₄ is formed from BaCl₂, Na₂SO₄ and K₂SO₄ we have

Amount of BaSO₄ from Na₂SO₄ is therefore;

X\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, Na_2SO_4}

Amount of BaSO₄ from K₂SO₄ is;

Y\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, K_2SO_4}

Molar mass of

BaSO₄ = 233.38 g/mol

Na₂SO₄ = 142.04 g/mol

K₂SO₄ = 174.259 g/mol

X\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, Na_2SO_4} = X\times\frac{233.38 }{142.04} = 1.643·X

Y\times\frac{Molar \, Mass \, of \, BaSO_4}{Molar \, Mass \, of \, K_2SO_4} = Y\times\frac{233.38 }{174.259 } = 1.339·Y

Therefore, we have

1.643·X + 1.339·Y = 0.298 g.....(2)

Solving equations (1) and (2) gives

The mass of SO₄⁻² in the sample is given by

Mass of sample = 0.298

Molar mass of BaSO₄ = 233.38 g/mol

Mass of Ba = 137.327 g/mol

∴ Mass of SO₄ = 233.38 g - 137.327 g = 96.05 g

Mass fraction of SO₄⁻² in BaSO₄ = 96.05 g/233.38 g = 0.412

Mass of SO₄⁻² in the sample is 0.412×0.298 = 0.123 g.

Percentage mass of SO₄⁻² = 41.2%

Solving equations (1) and (2) gives

X = 0.0773 g and Y = 0.1277 g.

8 0
3 years ago
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