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blsea [12.9K]
3 years ago
15

Fill in the blanka gas-like state of matter consisting of free electrons and atomic nuclei is __________

Chemistry
1 answer:
belka [17]3 years ago
7 0
Hi lovely,

The answer you're looking for would be Plasma.
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What is the relationship between atoms and mass?
castortr0y [4]

Answer:

Explanation:

A property closely related to an atom's mass number is its atomic mass. The atomic mass of a single atom is simply its total mass and is typically expressed in atomic mass units or amu.

6 0
3 years ago
What are three limitations of current cloaking technology.
kirill [66]

Explanation:

1.undetectable to electromagnetic waves

2.hiding an object from an illumination containing diffre t wave lengths become difficult as the object sizes grow.

3. reduce the scattering by two orders.

4 0
3 years ago
Calculate how many grams of oxygen form when 2.72 g of KCIOg reacts completely given the
34kurt

1.06g

Please refer to the image attached.

You first find the number of moles (n) for KClO3 as you have been given the mass. So n = mass/Mr gives you the moles that is 0.022 mol

Next you use the ratio 2:3 as per the equation where it's 2KClO3 ---> 3O2 so you just cross multiply and get the moles for oxygen.

Now that you know the number of moles for oxygen, you can use the same moles equation that you used earlier to find the mass. mass=n×Mr and so you get the answer as 1.06g of oxygen.

4 0
2 years ago
Naming Compounds of the Nonmetals
Xelga [282]

Nitrogen Dioxide is the Answer. If any doubt leave a comment

8 0
3 years ago
Read 2 more answers
In a coffe cup calorimeter, 50.0mL of 0.100M of AgNO3 and 50mL of 0.100M HCl are mixed to yield the following reaction:
Jet001 [13]

Answer:

The enthalpy change of the reaction is -66.88 kJ/mol.

Explanation:

Mass of the solution = m = 100 g

Heat capacity of the solution = c = 4.18 J/g°C

Initial temperature of the solutions before mixing = T_1=22.60^oC

Final temperature of the solution after mixing = T_2=23.40^oC

Heat gained by the solution due to heat released by reaction between HCl and silver nitrate = Q

Q=m\times c\times (T_2-T_1)

Q=100 g\times 4.18 J/g^oC\times (23.40^oC-22.60^oC)=334.4 J

Heat released due to reaction = Q' =-Q = -334.4 J

Moles of silver nitrate = n

Molarity of silver nitrate solution = 0.100 M

Volume of the silver nitrate solution = 50.0 mL = 0.050 L ( 1 mL = 0.001 L)

Moles =Molarity\times Volume (L)

n=0.100 M\times 0.050 L=0.005 mol

Enthalpy change of the reaction = \Delta H

=\Delta H=\frac{-334.4 J}{0.005 mol}=-66,880 J/mol=-66.88 kJ/mol

1 J = 0.001 kJ

The enthalpy change of the reaction is -66.88 kJ/mol.

7 0
3 years ago
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