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blsea [12.9K]
3 years ago
15

Fill in the blanka gas-like state of matter consisting of free electrons and atomic nuclei is __________

Chemistry
1 answer:
belka [17]3 years ago
7 0
Hi lovely,

The answer you're looking for would be Plasma.
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How can you overcome drawback of a chemaicl equation ? any three​
Shtirlitz [24]

Answer:

1.rate of reaction should be indicated by symbols 2.we should indicate physical states by sybloms 3.reversible reaction should be indicated by using double arrows

4 0
3 years ago
What is the primary cause of diffusion? some substances can dissolve in solvents heat added to a substance random internal motio
Nina [5.8K]

Answer:

random internal motion of atoms and molecule

Explanation:

The primary cause of diffusion is the random internal motion of atoms and molecules.

Randomness of atoms and molecules results in diffusion.

  • Diffusion is the movement of particles from a region of high concentration to that of lower concentration.
  • Substances often tend to spread out over the concentration gradient.
  • Therefore, they have this propensity to be randomized.
3 0
3 years ago
Does the production of a new gas by a substance represent a chemical property. Explain?
kompoz [17]

Yes, because you made a new substance to make a gas.

4 0
3 years ago
An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.
Stels [109]

Answer: The percent yield of the reaction is 77.0 %

Explanation:

2Pb+O_2\rightarrow 2PbO

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of lead}=\frac{451.4g}{207.2g/mol}=2.18moles

\text{Number of moles of lead oxide}=\frac{374.7g}{223.2g/mol}=1.68moles

According to stoichiometry:

2 moles of Pb produces = 2 moles of PbO_2

2.18 moles of Pb is produced by=\frac{2}{2}\times 2.18=2.18moles of PbO_2

Mass of PbO_2 =moles\times {\text {Molar mass}}=2.18\times 223.2g/mol=486.6

percent yield =\frac{374.7g}{486.6g}\times 100=77.0\%

3 0
3 years ago
A copper coin with a mass of 6.30 grams changes temperature in the sunshine from 20.0°C to 32.0°C. How much energy is transferre
mote1985 [20]

Answer:

The energy transferred is  28.5  j

calculation

energy is calculate  MCΔT  formula  where,

M(mass)= 6.30  grams

C(specific heat capacity)= 0.377 j/g

ΔT(change in temperature)= 32.0c- 20 c= 12 c

Energy is therefore= 6.30 g   x 0.377  j/g /c x   12 c =28.5 j

4 0
3 years ago
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