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3 years ago

29,32,35,38 what is the 50th term

Mathematics

1 answer:

ss7ja [257]3 years ago

3 0

Answer:

176

Step-by-step explanation:

add 3 to each number till you hit the 50th number

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Simplify.<br><br> square root of 63.

lions [1.4K]

Answer: 7.937

Step-by-step explanation: Calculator...

6 0

3 years ago

Read 2 more answers

For which equation would x = 5 be a solution?

tresset_1 [31]

Answer:

The second option.

3x + 6 = 21.

Step-by-step explanation:

3x + 6 = 21.

If x = 5, plug it in.

3 · 5 + 6 = 21

15 + 6 = 21

Hope this helps,

Davinia.

7 0

3 years ago

Factor <br><br> LaTeX: 7v^2+31v+12

bazaltina [42]

Answer:

(7v +3 ) ( v + 4 )

Step-by-step explanation:

7v^2+31v+12

(7v + ) ( v + )

12 = 1*12

2*6

3*4

7* 4 + 3 = 31

(7v +3 ) ( v + 4 )

6 0

3 years ago

Drag each tile to the correct box.

Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

$a=3$

$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

$g(x)=\frac{1}{5}(4)^x$

$f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}$

$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0

3 years ago

Someone help me please. I don't just want the answer, I need an explanation on how it's done too.

NARA [144]

Answer:

Below.

Step-by-step explanation:

f) (a + b)^3 - 4(a + b)^2

The (a+ b)^2 can be taken out to give:

= (a + b)^2(a + b - 4)

= (a + b)(a + b)(a + b - 4).

g) 3x(x - y) - 6(-x + y)

= 3x( x - y) + 6(x - y)

= (3x + 6)(x - y)

= 3(x + 2)(x - y).

h) (6a - 5b)(c - d) + (3a + 4b)(d - c)

= (6a - 5b)(c - d) + (-3a - 4b)(c - d)

= -(c - d)(6a - 5b)(3a + 4b).

i) -3d(-9a - 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b).

= (3d + 2c)(9a + 2b).

j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)

= a^2b^3(2a + 1) + 6ab^2(2a + 1)

= (2a + 1)( a^2b^3 + 6ab^2)

The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:

(2a + 1)ab^2(ab + 6)

= ab^2(ab + 6)(2a + 1).

4 0

3 years ago