I would solve the first equation for x and then sub that value into x in the second equation. That's the easiest way. x - 2y = 3 solved for x is x = 2y+3. Now sub that in for x in the second equation: 5(2y+3)+3y=2 and 10y + 15 + 3y = 2. 13y = -13, and y = -1. Now sub that y value into either equation to solve for x: x = 2(-1) + 3 gives us an x value of x = 1. Therefore, your solution to this system is (1, -1), first choice above.
P+q= 5x^2+2
q-p= -(x-2) (x+2)
I hope everythink is clearly :) If not just ask :)
answer for your question is starting when x^2-14x-95=0. Just Ignore this above this.
Answer:v=4
v=16
v=4/3
v=64/3
Step-by-step explanation: i just did the assignment.
