72 is the minimum grade he must get on the last test in order to have an average of 77.
<u>Step-by-step explanation:</u>
The grades of a student are given 72,91,78,72 and the grade of his last test is not given.
- You have to find the minimum grade the student shall get, so that the student average must be 77.
- The four grades are already given. Therefore, we need to find only the fifth grade.
The term average is defined as the sum of all the data in a set divided by the number of data in a set.
Here, the number of data is 5. (Because the students has 4 grades plus one grade for his last test).
The average he should get is 77.
Average = Sum of all grades / number of grades
Let, 'x' be the grade of the last test.
⇒ 77 = (72+91+78+72+x) / 5
⇒ 77 = (313+x) / 5
⇒ 385 = 313 + x
⇒ x = 385 - 313
⇒ x = 72
The minimum grade he must get on the last test is 72.
Answer:
y=1/2
Step-by-step explanation:
nswer:
Step-by-step explanat
|x+2| - 1 ≥ 5
|x+2| ≥ 5+1
|x+2| ≥ 6
x+2 ≥ 6 hoặc x+2 ≤ -6
+ với x+2 ≥ 6 x ≥ 6 – 2 x ≥ 4
+ với x+2 ≤ -6 x ≤ -6 – 2 x ≤ -8
(-∝;-8)∪(4;+∝)
According to the logarithmic property of base change, the correpta answer is option one or the first.
The logarithmic property of base change says that
loga (b) = logc (b) / logc (a)
Therefore the same property applies to this problem and the correct expression for this question is:
logb (x) / logb (a)
Answer: 2 or B hope this helped!
