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3 years ago

9

An object with a mass of 7.1 g raises the level of water in a graduated cylinder from 25.1 mL to 32.4 mL. What is the density of

the object?

1 answer:

jeka57 [31]3 years ago

5 0

Answer:

0.9726g/ml

0.9726g/cm³

Explanation:

Density is found by dividing mass by volume.

Density = mass/volume

mass = 7.1g

volume= the new level of water raised - the initial level of water

volume = 32.4 - 25.1

volume = 7.3 ml

Volume is the amount of space occupied by an object.meaning the amount of volume displaced by the object is its volume.

density = 7.1 /7.3

density = 0.9726g/ml

or 0.9726 g/cm³

If you need any clarification or more explanation pls do mention at the comment section.

hope this helps and if it does pls mark as branliest answer thx

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Sodium carbonate can be made by heating sodium bicarbonate: 2NaHCO3(s) → Na2CO3(s) + CO2(g) + H2O(g) Given that ΔH° = 128.9 kJ/m

Ad libitum [116K]

Answer:

[tex]128^{o}C[/tex]minimum temperature will the reaction become spontaneous.

Explanation:

$\Delta G=\Delta H-T \Delta S$

From the given,

$\Delta G^{o}=33.1$

$\Delta H^{o}=128.9kJ/mol$

$Temperature\,change=25+273=98K$

$33.1=128.9-298 \Delta S$

$\Delta S=0.322kJ/mol.K$

$\Delta G=\Delta H-T \Delta S$

$0=128.9-T(0.322)=401K=218^{o}C$

Therefore, $128^{o}C$ minimum temperature will the reaction become spontaneous.

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2 years ago

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

andre [41]

Complete question:

The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.

If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?

Answer:

After 210 s the concentration of SO2Cl2 will be 0.121 M

Explanation:

$ln\frac{[A_t]}{[A_0]} =-kt$

where;

At is the concentration of A at a time t

A₀ is the initial concentration of A

k is rate constant = 1.44×10⁻⁴ s⁻¹

t is time

ln(At/A₀) = -( 1.44×10⁻⁴)t

ln(At/0.125) = -( 1.44×10⁻⁴)210

ln(At/0.125) = -0.03024

$\frac{A_t}{0.125} = e^{-0.03024$

At/0.125 = 0.9702

At = 0.125*0.9702

At = 0.121 M

Therefore, after 210 s the concentration of SO2Cl2 will be 0.121 M

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2 years ago

Halogenated compounds are particularly easy to identify by their mass spectra because chlorine and bromine occur naturally as mi

12345 [234]

Answer:

The increasing order of masses of molecule ions:

118 g/mol(75.8%) , 120 g/mol(24.2%)

Explanation:

Chlorine occurs as 35-Cl (75.8%) and 37-Cl (24.2%).

Atomic mass of 35-Cl = 35 g/mol

Atomic mass of 37-Cl = 37 g/mol

Mass of Chlorocyclohexane in which 35-cl is present as a chlorine atom: $C_6H_{11}Cl$

$=6\times 12 g/mol+11\times 1 g/mol+1\times 35 g/mol=118 g/mol$

Mass of Chlorocyclohexane in which 37-Cl is present as a chlorine atom: $C_6H_{11}Cl$

$=6\times 12 g/mol+11\times 1 g/mol+1\times 37 g/mol=120 g/mol$

The increasing order of masses of molecule ions:

118 g/mol(75.8%) < 120 g/mol(24.2%)

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2 years ago

43 Which temperature change indicates an increase in the average kinetic energy of the molecules in a sample?(1) 15°C to 298 K (

aleksandrvk [35]

The increase in the average kinetic energy of the molecules needs the increase of temperature. The relation of ℃ and K is n ℃ = m K -273. So if we change all the K unit to ℃ unit, we can get the answer is (1).

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2 years ago

Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )

Fiesta28 [93]

This is an incomplete question, here is a complete question.

Consider the decomposition of a metal oxide to its elements, where M represents a generic metal.

$M_3O_4(s)\rightleftharpoons 3M(s)+2O_2(g)$

Substance ΔG°f (kJ/mol)

M₃O₄ -9.50

M(s) 0

O₂(g) 0

What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? delta G°rxn = kJ / mol.

What is the equilibrium constant of this reaction, as written, in the forward direction at 298 K?

What is the equilibrium pressure of O₂(g) over M(s) at 298 K?

Answer :

The Gibbs energy of reaction is, 9.50 kJ/mol

The equilibrium constant of this reaction is, 0.0216

The equilibrium pressure of O₂(g) is, 0.147 atm

Explanation :

The given chemical reaction is:

$PCl_3(l)\rightarrow PCl_3(g)$

First we have to calculate the Gibbs energy of reaction $(\Delta G^o)$ .

$\Delta G^o=G_f_{product}-G_f_{reactant}$

$\Delta G^o=[n_{M(s)}\times \Delta G^0_{(M(s))}+n_{O_2(g)}\times \Delta G^0_{(O_2(g))}]-[n_{M_3O_4(s)}\times \Delta G^0_{(M_3O_4(s))}]$

where,

$\Delta G^o$ = Gibbs energy of reaction = ?

n = number of moles

Now put all the given values in this expression, we get:

$\Delta G^o=[3mole\times (0kJ/mol)+2mole\times (0kJ/mol)]-[1mole\times (-9.50kJ/K.mol)]$

$\Delta G^o=9.50kJ/mol$

The Gibbs energy of reaction is, 9.50 kJ/mol

Now we have to calculate the equilibrium constant of this reaction.

The relation between the equilibrium constant and standard Gibbs free energy is:

$\Delta G^o=-RT\times \ln K$

where,

$\Delta G^o$ = standard Gibbs free energy = 9.50kJ/mol = 9500 J/mol

R = gas constant = 8.314 J/K.mol

T = temperature = 298 K

K = equilibrium constant = ?

$9500J/mol=-(8.314J/K.mol)\times (298K)\times \ln (K)$

$K=0.0216$

The equilibrium constant of this reaction is, 0.0216

Now we have to calculate the equilibrium pressure of O₂(g).

The expression of equilibrium constant is:

$K=(P_{O_2})^2$

$0.0216=(P_{O_2})^2$

$P_{O_2}=0.147atm$

The equilibrium pressure of O₂(g) is, 0.147 atm

5 0

3 years ago