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Firdavs [7]
3 years ago
11

In standardizing a naoh solution a student found that 25.55cm of base neutralize exactly 21.35cm of 0.12M HCl find the molarity

of the NaoH
Chemistry
1 answer:
nalin [4]3 years ago
6 0

Answer:

O.1M

Explanation:

First let's generate a balanced equation for the reaction

NaOH + HCl —>NaCl + H2O

From the equation,

The ratio of the acid to base is 1:1.

From the question, we obtained the following:

Ma = Molarity of acid = 0.12M

Va = volume of acid = 21.35cm3

Vb = volume of base = 25.55cm3

Mb = Molarity of base =?

We obtained nA(mole of acid) and nB(mole of base) to be 1

The molarity of the base can be calculated for using:

MaVa/ MbVb = nA / nB

0.12x21.35 / Mb x 25.55 = 1

Cross multiply to express in linear form

Mb x 25.55 = 0.12x21.35

Divide both side by 25.55

Mb = (0.12x21.35) / 25.55

Mb = 0.1M

The molarity of the base is 0.1M

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3 years ago
The molecular weight of an ionic compound is 118.9 g/mol. the ions in the unknown are sodium, oxygen, and bromine. what is the n
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<span>
M(NaBrO</span>ₓ) = 118.9 g/mol; <span>molecular weight of an ionic compound.
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3Fe+4H2O--&gt;Fe3O4+4H2 What is the mole ratioof Fe3O4 to Fe?
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Hope this helps!
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Read 2 more answers
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