To be able to answer this equations, we must set given information. Suppose the reaction to yield NO is:
N₂ + O₂ → 2 NO
Next, suppose you have 1 g of each of the reactants. Determine first which is the limiting reactant.
1 g N₂ (1 mol N₂/ 28 g)(2 mol NO/1 mol N₂)= 0.07154 mol NO present
Number of molecules = 0.07154 mol NO(6.022×10²³ molecules/mol)
<em>Number of molecules = 4.3×10²² molecules NO present</em>
Nonmetal atoms would share electrons in a covalent bonding.
Hope this helped! :D
<h3>Answer:</h3>
<u>Easy</u><u>!</u><u>!</u>
2+<u>1</u><u>7</u>=19
#<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>that</em><em> </em><em>helps</em>
24 minus 8 is 16
5 times 60 is 300
300 times 16 is 4800.
She winks 4800 times a day
what is that????????????????