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dybincka [34]
3 years ago
14

Hot, molten rock deep below Earth’s surface is called lava mantle rock parent rock magma

Chemistry
1 answer:
Rashid [163]3 years ago
6 0

Answer:

I think it is Magma

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What is the nuclear charge of a berrylium atom?
ICE Princess25 [194]

Answer:

The charge on the nucleus of an atom; controlled by the number of protons and electrons present in an atom.

Explanation:

4 0
3 years ago
Dalton’s Law CalculationA mixture of H₂, N₂ and Ar gases is present in a steel cylinder. The total pressure within the cylinder
Zolol [24]

Answer:

A) The partial presssure of CO₂ is 167 mm Hg

B) The partial presssure of N₂ is 354 mm Hg

C) The partial presssure of Ar is 235 mm Hg

D) The partial presssure of H₂ is 86 mm Hg

Explanation:

Dalton's law of partial pressures is basically expressed by the following statement:

The total pressure of a mixture is equal to the sum of the partial pressures of its components.

So initially we have:

P_{T}= total presure of the system (675 mm Hg).

P_{N_2}= partial pressure of N₂ (354 mm Hg).

P_{Ar}= partial pressure of Ar (235 mm Hg).

Using Dalton's law we can find the partial pressure of H₂:

P_{T}=P_{N_2}+P_{Ar}+P_{H_2}

675 mm Hg=354 mm Hg + 235 mm Hg + P_{H_2}

P_{H_2}= 675 mm Hg - 354 mm Hg - 235 mm Hg

P_{H_2}=86 mm Hg

If CO₂ gas is added to the mixture, at constant temperature, and the volume is the same, the difference between the new total pressure and the previous total pressure is equal to the partial pressure of CO₂.

P_{T}=P_{N_2}+P_{Ar}+P_{H_2}+P_{CO_2}

842 mm Hg= 354 mm Hg + 235 mm Hg + 86 mm Hg + P_{CO_2}

P_{CO_2}= 842 mm Hg - 354 mm Hg - 235 mm Hg - 86 mm Hg

P_{CO_2}= 167 mm Hg

4 0
3 years ago
Now they feel it is best to have you identify an unknown gas based on its properties. Suppose 0.508 g of a gas occupies a volume
pishuonlain [190]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

             mass = 0.508 g,               Volume = 0.175 L

             Temperature = (25 + 273) K = 298 K,       P = 1 atm

As per the ideal gas law, PV = nRT.

where,  n = no. of moles = \frac{mass}{\text{molar mass}}

Hence, putting all the given values into the ideal gas equation as follows.

               PV = \frac{mass}{\text{molar mass}} \times RT            

           1 atm \times 0.175 L = \frac{0.508 g}{\text{molar mass}} \times 0.0821 L atm/ K mol \times 298 K  

                            = 71.02 g

As the molar mass of a chlorine atom is 35.4 g/mol and it exists as a gas. So, molar mass of Cl_{2} is 70.8 g/mol or 71 g/mol (approx).

Thus, we can conclude that the gas is most likely chlorine.

4 0
3 years ago
How many moles of Au2S3 is required to form 56 grams of H2S at STP?
Law Incorporation [45]

Answer:

0.55 mol Au₂S₃

Explanation:

Normally, we would need a balanced equation with masses, moles, and molar masses, but we can get by with a partial equation, if the S atoms are balanced.

1. Gather all the information in one place:

M_r:                          34.08

          Au₂S₃ + … ⟶ 3H₂S + …  

m/g:                             56  

2. Calculate the moles of H₂S

Moles of H₂S = 56 g H₂S × (34.08 g H₂S/1 mol H₂S)

                      = 1.64 mol H₂S

3. Calculate the moles of Au₂S₃

The molar ratio is 1 mol Au₂S₃/3 mol H₂S.

Moles of Au₂S₃ = 1.64 mol H₂S × (1 mol Au₂S₃/3 mol H₂S)

                         = 0.55 mol Au₂S₃

7 0
4 years ago
An ideal liquid mixture of benzene and toluene (50% by volume each) is used in a plant at 27°C and 1 atm. Determine (a) the mixt
cestrela7 [59]

Answer:

See explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

7 0
3 years ago
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