Answer:
The runner's average acceleration is 0.102 m/s²
Explanation:
The runner accelerates from 5 m/s to 5.2 m/s and covering 10 m
We need to find the runner's average acceleration
The given is:
→ Initial velocity 5 m/s
→ Final velocity 5.2 m/s
→ Distance 10 meters
→ Acceleration ?
We need a suitable rule for the given
→ v² = u² + 2 a s
where v is the final velocity, u is the initial velocity, a is the acceleration
and s is the distance
Substitute the values above in the rule
→ (5.2)² = (5)² + 2 a (10)
→ 27.04 = 25 + 20 a
Subtract 25 from both sides
→2.04 = 20 a
Divide both sides by 20
→ a = 0.102 m/s²
<em>The runner's average acceleration is 0.102 m/s²</em>
Answer:
measuring cup
The most popular tool used to measure capacity is the measuring cup.
Answer:
F= 4788 N
Explanation:
Because the car moves with uniformly accelerated movement we apply the following formula:
vf²=v₀²+2*a*d Formula (1)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
d=36.9 m
v₀=14.0 m/s m/s
vf= 0
Calculating of the acceleration of the car
We replace dta in the formula (1)
vf²=v₀²+2*a*d
(0)²=(14)²+2*a*(36.9)
-(14)²= (73.8) *a
a= - (196) / (73.8)
a= - 2.66 m/s²
Newton's second law of the car in direction horizontal (x):
∑Fx = m*ax Formula (2)
∑F : algebraic sum of the forces in direction x-axis (N)
m : mass (kg)
a : acceleration (m/s²)
Data
m=1800 Fkg
a= - 2.66 m/s²
Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :
We replace data in the formula (2)
-F= (1800 kg) * ( -2.66 m/s²
)
F= 4788 N
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