The answer is Sagittarius A, a very large black hole.
Answer and Explanation:
Every lens have two focal points each focal point is present on the either side of the lens. In lenses when light comes from the infinite it passes through the focal point it is true for both converging as well as diverging lens. In mirror there is only one focal point as it one face is covered but in lens light can pass through side of the lens so it has two focal point
<u>Answer:</u> The specific heat of ice is 2.11 J/g°C
<u>Explanation:</u>
When ice is mixed with water, the amount of heat released by water will be equal to the amount of heat absorbed by ice.
The equation used to calculate heat released or absorbed follows:
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
......(1)
where,
q = heat absorbed or released
= mass of ice = 12.5 g
= mass of water = 85.0 g
= final temperature = 22.24°C
= initial temperature of ice = -15.00°C
= initial temperature of water = 25.00°C
= specific heat of ice = ?
= specific heat of water = 4.186 J/g°C
Putting values in equation 1, we get:
![12.5\times c_1\times (22.24-(-15))=-[85.0\times 4.186\times (22.24-25)]](https://tex.z-dn.net/?f=12.5%5Ctimes%20c_1%5Ctimes%20%2822.24-%28-15%29%29%3D-%5B85.0%5Ctimes%204.186%5Ctimes%20%2822.24-25%29%5D)
Hence, the specific heat of ice is 2.11 J/g°C
Answer:
The experimental scientist
I had the SAME problem, put down Radiation and it’s thermal/light.
