Answer:
Explanation:
Consider downward displacement first .
downward displacement h = 38 m .
downward acceleration = g
downward initial velocity u = 0
h = ut + 1/2 g t ²
38 = 0 + 9.8 t ²
t = 1.97 s
During this period , there will be horizontal displacement with initial velocity u = 10 m /s and acceleration a = 1.6 m /s²
s = ut + 1/2 a t²
= 10 x 1.97 + .5 x 1.6 x 1.97²
= 19.7 + 3.10
= 22.8 m
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Answer:
3.33 seconds
Explanation:
We can use the velocity formula [ v = u + at ] to solve.
Find the value "u".
135km/h -> 135km*1000m/3600s -> 37.5m/s
Find the value "v".
75km/h -> 75km*1000m/3600s -> 20.83m/s
Keep in mind we are dealing with "deceleration" so when we input 5.0m/s into the formula, it will be a negative value.
Now, find "t" which is the value we aren't given with the values we're given in the question.
20.83 = 37.5 - 5t
-16.67 = -5t
3.33 = t
Best of luck!
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