The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
 11
 11 
⇒x=11t
Area of square=
Area of square= {as the length of side is 11t}{varies by time}
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
Learn more about The function of the area of the square is A(t)=121
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
 11
 11 
⇒x=11t
Area of square=
Area of square= {as the length of side is 11t}{varies by time}
{as the length of side is 11t}{varies by time}
Area of square=121
Therefore,The function of the area of the square is A(t)=121
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Since segments ST and PQ are parallel, triangles SRT and PRQ are similar due to the AAA postulate. In general, the ratio between the corresponding sides of two similar triangles is constant; therefore,

Furthermore,

Finding PR and RS,

Then,


Solving for PS,

Solve the quadratic equation in terms of PS, as shown below
![\begin{gathered} \Rightarrow PS^2+16PS-132=0 \\ \Rightarrow PS=\frac{-16\pm\sqrt[]{16^2-4(-132)}}{2}=\frac{-16\pm28}{2} \\ \Rightarrow PS=-22,6 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5CRightarrow%20PS%5E2%2B16PS-132%3D0%20%5C%5C%20%5CRightarrow%20PS%3D%5Cfrac%7B-16%5Cpm%5Csqrt%5B%5D%7B16%5E2-4%28-132%29%7D%7D%7B2%7D%3D%5Cfrac%7B-16%5Cpm28%7D%7B2%7D%20%5C%5C%20%5CRightarrow%20PS%3D-22%2C6%20%5Cend%7Bgathered%7D)
And PS is a segment; therefore, it has to be positive.
Hence, the answer is PS=6
 
        
             
        
        
        
It’s True.. you take the “extreme” variable from each proportion and cross multiply them before setting them equal to the product of the two “means” (which are just the other 2 numbers in the proportions).
        
             
        
        
        
The first one is 17 13/15 the second one is 22 1/20
        
             
        
        
        
<span>6( 5-8x) +12= -54 
30-48x+12=-54 this comes from distributing(multiplying) 6x5 and 6 times -8x
30+12-48x=-54 you have to add the coefficients 30+12
42-48x=-54  
-42        -42 
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-48x=-96 divide by -48
x=2</span>