If this is Textbook work- use SLADER (the app or the website)
substitution and elimination means that you need to use one equation and substitute it in place of some variable in the other equation.
Consider the above two equations.
Take equation 1, which is 4x-2y=22 => x=(22+2y)/4
substitute the x value gained above in equation 2.
so, 2((22+2y)/4)+4y=6
22+2y+8y=12 => 10y = -10 => y= -1.
Substitute y= -1 in x value obtained in the beginning.
So, x= (22 - 2)/4 => 5.
There fore, x= 5 and y= -1
Hope it helps.
X is 35, if you follow the rules of alternate angles
Answer:
4
Step-by-step explanation:
lim (x^2 - 4) / (x - 2)
x --> 2
When we plug x =2, we get
(2^2 - 4) / (2 - 2)
= (4 - 4)/(2 - 2)
= 0 /0
Which is undefined.
Now we have to use L'hospital rule. Which says we need to differentiate the numerator and the denominator and apply the limit.
When we differentiate x^2 -4, we get 2x
When we differentiate x -2, we get 1
lim 2x/1
x --> 2
Now apply, the limit x = 2
2(2)/1
= 4/1
= 4
Therefore, limit of this function is 4, when x tends to 2.
Hope you will understand the concept.
Thank you.
F(1) = (1)^3 + 2(1)^2 - 5(1) - 6 = 1 + 2 - 5 - 6 = -8; x = 1 is not a solution to the polynomial.
f(-1) = (-1)^3 + 2(-1)^2 - 5(-1) - 6 = -1 + 2 + 5 - 6 = 0; x = -1 is a solution to polynomial.
From the options, a or c has x = -1, both has x = , so lets check for x = 3
f(3) = (3)^3 + 2(3)^2 - 5(3) - 6 = 27 + 18 - 15 - 6 = 24; x = 3 is not a solution to the polynomial.
Therefore the solutions to the polynomial are x = -3, x = -1, x = 2
