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erastova [34]
3 years ago
8

The ___ is always located across from the right angle.

Mathematics
2 answers:
kramer3 years ago
7 0
The answer to your question is “Hypotenuse”
Kryger [21]3 years ago
6 0

Elloo!

You have asked: The ___ is always located across from the right angle.

The correct answer would be a "Hypotenuse".

It should be filled in like <em>The Hypotenuse is always located across from the right angle.</em>

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Let a be a rational number and b be an irrational number. Which of the following are true statements?(there is more than 1 answe
kramer
<span>A.) the sum of a and b is never rational.
This is a true statement. Since an irrational umber has a decimal part that is infinite and non-periodical, when you add a rational number to an irrational number, the result will have the same infinite non periodical decimal part, so the new number will be irrational as well.

</span><span>B.) The product of a and b is rational
This one is false. Zero is a rational number, and when you multiply an irrational number by zero, the result is always zero.

</span><span>C.) b^2 is sometimes rational
This one is true. When you square an irrational number that comes from a square root like </span>\sqrt{2}, you will end with a rational number: ( \sqrt{2} )^{2}=2, but, if you square rationals from different roots than square root like \sqrt[3]{2}, you will end with an irrational number: \sqrt[3]{2^{2} } = \sqrt[3]{2}. 

<span>D.) a^2 is always rational
This one is false. If you square a rational number, you will always end with another rational number.

</span><span>E.) square root of a is never rational
</span>This one is false. The square root of perfect squares are always rational numbers: \sqrt{64} =8, \sqrt{16} =4,...

F.) square root of b is never rational
This one is true. Since the square root of any non-perfect square number is irrational, and all the irrational numbers are non-perfect squares, the square root of an irrational number is always irrational.

We can conclude that given that<span> a is a rational number and b be an irrational number, A, C, D, and F are true statements.</span>
4 0
3 years ago
16.The least common denominator of 1/2, 1/8, and 1/10 isO A. 10.OB. 80.C. 40.D. 16.nMark for review Awill be biabliabted on the
tangare [24]

Given

The numbers, 1/2, 1/8, and 1/10.

To find: The least common denominator.

Explanation:

It is given that,

1/2, 1/8, and 1/10 .

Then,

Therefore, the LCM is,

\begin{gathered} LCM=2\times2\times2\times5 \\ =40 \end{gathered}

Hence, the least common denominator is 40.

6 0
1 year ago
A parabola has zeros at (5,0) and (-3,0) and passes through point (6,18) determine the axis of symmetry
worty [1.4K]

Answer:

The axis of symmetry is x=1

Step-by-step explanation:

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

In this problem we have a vertical parabola open upward

The x-coordinate of the vertex is equal to the midpoint between the zeros of the parabola

so

x=\frac{5-3}{2}=1

therefore

The axis of symmetry is x=1

5 0
3 years ago
+<br> Find the are of the triangle
Yuliya22 [10]
Where’s the picture. Please show it
4 0
3 years ago
Number 2 please help
Sveta_85 [38]

Answer:

you just have to check the first and the third box

Step-by-step explanation:

put each into slop intercept form

y+6=-5(x-2) is the same as y=-5x+4

y-2=-5(x+6) is the same as y=-5x-28

y=-5x+4

y=-5x-28

all of them have a slope of -5, but you need to plug in (2,-6) to see which on is true

5 0
3 years ago
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