Answer:
The rational number equivalent to 3.24 repeating is 321/99
Step-by-step explanation:
To convert the decimal number to a rational number we can state this number and its multiples of 10, trying to find two number with identical decimal parts:
n=3.24242424...
10n=32.4242424....
100n=324.2424242...
Now, 100n and n have the same decimal part, then by subtracting these numbers we obtain:
100n-n=324.24242424...-3.24242424... = 321
99n = 321
n = 321/99
Answer:
$40
Step-by-step explanation:
x is the original price of the gift
(10% of x) is the value of the discount
(10% of x) = 10/100 . x = 0.1 x
0.1 x is the value of the discount
x - (10% of x) is what was paid, after the discount
x - 0.1 x = 0.9 x
0.9 x is what was paid
4 children paid $9/each
4 times $9 = $36
$36 is the total amount that was paid by the children
$36 = 0.9 x
$36 / 0.9 = x
x = $36 / 0.9 = 360 / 9
x = 40
;-)
The question is defective, or at least is trying to lead you down the primrose path.
The function is linear, so the rate of change is the same no matter what interval (section) of it you're looking at.
The "rate of change" is just the slope of the function in the section. That's
(change in f(x) ) / (change in 'x') between the ends of the section.
In Section A:Length of the section = (1 - 0) = 1f(1) = 5f(0) = 0change in the value of the function = (5 - 0) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
In Section B:Length of the section = (3 - 2) = 1 f(3) = 15f(2) = 10change in the value of the function = (15 - 10) = 5Rate of change = (change in the value of the function) / (size of the section) = 5/1 = 5
Part A:The average rate of change of each section is 5.
Part B:The average rate of change of Section B is equal to the average rate of change of Section A.
Explanation:The average rates of change in every section are equalbecause the function is linear, its graph is a straight line,and the rate of change is just the slope of the graph.
Side-Side-Side Theorem, Side-Angle-Side, Angle-Angle-Side, Angle-Side-Angle, and Hypotenuse-Leg for right triangles.
For example, for Side-Side-Side, if you prove all 3 sides of the triangle are congruent, then the triangle is congruent.
