Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
Me neither. I used to know, good luck!
Answer:
ummmmm..... ykw I cant do that but I will give out free brainly points sooo ya (on a question)
Step-by-step explanation:
1) Negative five
-5 x 4 = -20
2) Negative eighty
-80 / -4 = 20
3) Negative 1/5
(-1/5) x (-20) = 4
4) Negative eighty
(-80) / 4 = -20
Answer:
64 + 28 = 92
Step-by-step explanation:
Split the figure in half creating two triangles and a square.
length and width for the square would be 8ft and 8ft. Multiply both for 64 to be the area.
7ft and 4ft are the height and base for the triangles.
In this case, just multiple 7 and 4 because normally you would need to divide the product by 2 however since there are two triangles it negates the step.
