We use different models for different types of variation. For example, linear variation is associated with the formula y=ax, or the more familiar y=mx+b (the equation of a straight line). Cubic variation: y=a*x^3. In the present case we're discussing quadratic variation; perhaps that will ring a bell with you, reminding you that y=ax^2+bx+c is the general quadratic function.
Now in y our math problem, we're told that this is a case of quadratic variation. Use the model y=a*x^2. For example, we know that if x=2, y =32. Mind substituting those two values into y=a*x^2 and solving for y? Then you could re-write y=a*x^2 substituting this value for a. Then check thisd value by substituting x=3, y=72, and see whether the resulting equation is true or not. If it is, your a value is correct. But overall I got 16!
Comment
I'm going to take a guess at this and say what you meant is 2401 = 7^(6 - 2x)
Step One
Find out the power of 7 that will equal 2401.
You could do it like this.
7^y = 2401 and just guess at some values.
y 7^y
1 7
2 49
3 7 * 7 * 7 = 343
4 7 * 7 * 7 * 7 = 2401 So the answer is 4
7^4 = 2401
Step 2
Equate the powers.
2401 = 7^(6 - 2x)
7^4 = 7^ (6 - 2x)
4 = 6 - 2x Subtract 6 from both sides.
4 - 6 = - 2x
-2 = - 2x divide by - 2
-2/-2 = x
x = 1 <<<<<<<<<<<<<answer
Subtract 3 from each side to isolate the x and you get x=y-3
Answer:
x-6 = -4
Step-by-step explanation:
3x - 8= -2
Add 8 to each side
3x - 8+8= -2+8
3x = 6
Divide by 3
3x/3 = 6/2
x =2
We want to find x-6
2-6 = -4
Answer:
A: 28 cm
Step-by-step explanation:
