Answer:
try b=32
Step-by-step explanation:
Answer:
(tan(theta)-1)^3
= (tan(theta)-1)(tan(theta)-1)(tan(theta)-1)
= (tan^2(theta)-2tan(theta)+1)(tan(theta)-1)
= tan^3(theta)-2tan^2(theta)+tan(theta)-tan^2(theta)+2tan(theta)-1
= tan^3(theta)-3tan^2(theta)+3tan(theta)-1
Hope this helps :)
STEP 1:
determine equations needed
x= # of $10 tickets
y= # of $14 tickets
QUANTITY EQUATION
x + y= 800
COST EQUATION
$10x + $14y= $9,040
STEP 2:
multiply quantity equation by -14
-14(x + y)= -14(800)
-14x - 14y= -11,200
STEP 3:
add new quantity equation in step 2 to cost equation of step 1 to solve for x using elimination
-14x - 14y= -11,200
10x + 14y= 9040
y term cancels out
-4x= -2160
divide both sides by -4
x= 540 ten dollar tickets
STEP 4:
substitute x value in step 3 into either original equation
x + y= 800
540 + y= 800
subtract 540 from both sides
y= 260 fourteen dollar tickets
ANSWER: There were 540 $10 tickets and 260 $14 tickets sold.
Hope this helps! :)
71/20 i believe. Is it multiple choice?
1 km=0.621mi
xkm=106 mi
x=106/0.621=170.66
b is the answer
