Question

Determine the Darcy friction factor for a fluid flowing in a pipe with diameter 0.01 metres, flowing at 0.03 m/s. The fluid density is 36.4 kg/m and viscosity is 0.651 Pa*s. The pipe absolute roughness is 0.00062459 m. Give your answer rounded to the nearest whole number.

Answer 1

Explanation:

The given data is as follows.

Diameter of pipe, D = 0.01 m

Velocity V = 0.03 m/s

Fluid density = 36.4 $kg/m^{3}$

Viscosity = 0.651 Pa-s

Formula to calculate Reynold number is as follows.

Re = $diameter \times velocity \times \frac{density}{viscosity}$

     = $0.01 \times 0.03 \times \frac{36.4}{0.651}$

     = 0.01677

Since,  Re < 2100. This means that the flow is laminar.

So, for laminar flow in pipes,

Darcy friction factor f = $\frac{64}{Re}$

                                   = $\frac{64}{0.01677}$

                                    = 3816

Thus, we can conclude that the Darcy friction factor value is 3816.