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algol13
3 years ago
13

Determine the Darcy friction factor for a fluid flowing in a pipe with diameter 0.01 metres, flowing at 0.03 m/s. The fluid dens

ity is 36.4 kg/m and viscosity is 0.651 Pa*s. The pipe absolute roughness is 0.00062459 m. Give your answer rounded to the nearest whole number.
Chemistry
1 answer:
OLga [1]3 years ago
7 0

Explanation:

The given data is as follows.

Diameter of pipe, D = 0.01 m

Velocity V = 0.03 m/s

Fluid density = 36.4 kg/m^{3}

Viscosity = 0.651 Pa-s

Formula to calculate Reynold number is as follows.

Re = diameter \times velocity \times \frac{density}{viscosity}

     = 0.01 \times 0.03 \times \frac{36.4}{0.651}

     = 0.01677

Since,  Re < 2100. This means that the flow is laminar.

So, for laminar flow in pipes,

Darcy friction factor f = \frac{64}{Re}

                                   = \frac{64}{0.01677}

                                    = 3816

Thus, we can conclude that the Darcy friction factor value is 3816.

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