Answer:
m = B²qR² / 2 V
Explanation:
If v be the velocity after acceleration under potential difference of V
kinetic energy = loss of electric potential energy
1/2 m v² = Vq ,
v² = 2 Vq / m ----------------------- ( 1 )
In magnetic field , charged particle comes in circular motion in which magnetic force provides centripetal force
magnetic force = centripetal force
Bqv = mv² / R
v = BqR / m
v² = B²q²R² / m² ------------------------- (2)
from (1) and (2)
B²q²R² / m² = 2 Vq / m
m = B²q²R² / 2 Vq
m = B²qR² / 2 V
The answer is C, individuals copy works to view at a later time.
The electrostatic force between two charges q1 and q2 is given by

where

is the Coulomb's constant

is the distance between the two charges.
In our problem, the two charges are two electrons, so their charges are equal and equal to

By substituting these values, we find the intensity of the force between the two electrons:

This is the magnitude of the force each electron exerts to the other one. The direction is given by the sign of the charges: since the two electrons have same charge, they repel each other, so the force exerted by electron 1 is toward electron 2 and viceversa.
Answer:
0.2
Explanation:
Horizontal force=100N
Weight of crate=500 N
We have to find the coefficient of kinetic friction.
Normal ,N=Weight=500N
Horizontal force,
Where
=Horizontal force
N=Normal force
=Coefficient of kinetic friction
Substitute the values in the formula


Hence, the coefficient of kinetic friction =0.2