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kompoz [17]
4 years ago
13

Help me please!! asap!

Physics
2 answers:
anygoal [31]4 years ago
8 0

Explanation:

The circuit wouldn't work because if you remove 1 light bulb all of them will stop working because they're all conected

astraxan [27]4 years ago
5 0
I would say A because then there wouldn’t be constancy between both sides of the battery
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Why is the combination of two protons and two neutrons stable, but two protons and one neutron is not?
RideAnS [48]
Because it's unbalanced.
4 0
3 years ago
In a mass spectrometer a particle of mass m and charge q is accelerated through a potential difference V and allowed to enter a
Ghella [55]

Answer:

m = B²qR² / 2 V

Explanation:

If v be the velocity after acceleration under potential difference of V

kinetic energy  = loss of electric potential energy

1/2 m v² = Vq ,

v² = 2 Vq / m ----------------------- ( 1 )

In magnetic field , charged particle comes in circular motion in which magnetic force provides centripetal force

magnetic force = centripetal force

Bqv = mv² / R

v = BqR / m

v² = B²q²R² / m²  ------------------------- (2)

from (1) and (2)

B²q²R² / m²  = 2 Vq / m

m = B²q²R² / 2 Vq

m = B²qR² / 2 V

7 0
3 years ago
Time shifting occurs when _______.
Svet_ta [14]
The answer is C, individuals copy works to view at a later time.
4 0
4 years ago
Read 2 more answers
Two electrons are separated by a distance of 3.00 x 10^-6 meter. What are the magnitude and direction of the electrostatic force
Brilliant_brown [7]
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
where 
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
r=3.00 \cdot 10^{-6} m is the distance between the two charges.

In our problem, the two charges are two electrons, so their charges are equal and equal to 
q_1=q_2=q=-1.6 \cdot 10^{-19}C

By substituting these values, we find the intensity of the force between the two electrons:
F=(8.99 \cdot 10^9 N m^2 C^{-2})  \frac{(-1.6 \cdot 10^{-19}C)(-1.6 \cdot 10^{-19}C)}{(3.00 \cdot 10^{-6} m)^2}=2.6 \cdot 10^{-17}N

This is the magnitude of the force each electron exerts to the other one. The direction is given by the sign of the charges: since the two electrons have same charge, they repel each other, so the force exerted by electron 1 is toward electron 2 and viceversa.
5 0
3 years ago
A horizontal force of 100 N is used to pull a crate, which weighs 500 N, at constant velocity across a horizontal floor. What is
Ilya [14]

Answer:

0.2

Explanation:

Horizontal force=100N

Weight of crate=500 N

We have to find the coefficient of kinetic friction.

Normal ,N=Weight=500N

Horizontal force,F_x=\mu_kN

Where F_x=Horizontal force

N=Normal force

\mu_k=Coefficient of kinetic friction

Substitute the values in the formula

100=\mu_k(500)

\mu_k=\frac{100}{500}=0.2

Hence, the coefficient of kinetic friction =0.2

8 0
3 years ago
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