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balu736 [363]
3 years ago
6

How important friction is?

Physics
1 answer:
kirill [66]3 years ago
3 0

Friction is important because;

  • It enables us to walk due to the grip our feet have on the ground.
  • It enables the planes to fly due to the drag force.
  • It enables vehicles to move and to stop due to brakes and tire marks
  • Friction enables us to write using a pen.
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A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
nexus9112 [7]

Answer:

y=2.64m

Explanation:

Given data

Ball one

mass m₁=3.0kg

velocity v₁=20 m/s

Ball second

mass m₂=2.0 kg

velocity v₂=12 m/s

First we need the speed of combined ball.Since the system conserves the linear momentum

p_{i}=p_{f}\\m_{1}v_{1}+m_{2}v_{2}=m_{t}v_{t}

So the combined velocity vt is:

v_{t}=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{t}}\\

Since the two balls 1 and 2 are moving in opposite direction

So

v_{t}=\frac{m_{1}v_{1}-m_{2}v_{2}}{m_{t}}\\

Substitute the given values

v_{t}=\frac{(3kg)(20m/s)-(2kg)(12m/s)}{(3+2)kg}\\ v_{t}=7.2 m/s

We have the equation for motion with constant acceleration is given by:

v^2=v_{o}^2+2g(y-y_{o})\\

At initial position y₀=0 and vt=v-v₀

So

v^{2}=v_{o}^2+2g(y-0)\\ y=\frac{v^2-v_{o}^2}{2g}\\ y=\frac{v_{t}^2}{2g}\\ y=\frac{(7.2m/s)^2}{2(9.8m/s^2)}\\ y=2.64m

   

8 0
3 years ago
Which of the following is a type of wave that travels at a right angle relative to the direction of motion?
kramer
"Transverse" wave is the type of wave among the following choices given in the question that <span>travels at a right angle relative to the direction of motion. The correct option among all the options that are given in the question is the fourth option or the last option. I hope that this is the answer that has come to your help.</span>
3 0
3 years ago
Specific Heat and Thermal energy question. 30 points, will give brainliest. Please answer. Pic attached
Kruka [31]

Answer:

.69

Explanation:

6 0
3 years ago
Read 2 more answers
How much force does it take to accelerate a 50.8 kg person at 3.50 m/s^2?
Vikki [24]

Apply Newton's second law to the person's motion:

F = ma

F = net force, m = mass, a = acceleration

Given values:

m = 50.8kg, a = 3.50m/s²

Plug in and solve for F:

F = 50.8(3.50)

F = 178N

8 0
3 years ago
A ball rolls downhill with a constant acceleration of 4m/s squared. If it started from rest,it’s velocity at the end of 3 meters
vladimir2022 [97]

Answer:

4.9 m/s

Explanation:

Since the motion of the ball is a uniformly accelerated motion (constant acceleration), we can solve the problem by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the ball in this problem,

u = 0 (it starts from rest)

a=4 m/s^2 is the acceleration

s = 3 m is the distance covered

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(4)(3)}=4.9 m/s

3 0
3 years ago
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