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2 years ago

A bullet travels at 850 m/s. How long will it take a bullet to go 1000 m?

Physics

1 answer:

Lady_Fox [76]2 years ago

3 0

Answer:

I say 150 because i aded 850+150= 1000 so yea thats how i got my answer

Explanation:

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.2, A car starting from rest has an acceleration of

riadik2000 [5.3K]

Answer: 2.5 m/s and 6.25 m

Explanation:

u = 0

a = 0.5 m/s²

t = 5 s

v = u + at

= 0 + 0.5 × 5

= <u>2.5 m/s</u>

s = ut + 1/2 at²

= 1/2 × 2.5 × 5

=<u> 6.25 m</u>

7 0

4 years ago

5. If x = 0.6 and y = 5, the value of 2(xy)^3 is...

taurus [48]

Explanation:

=2(0.6 * 5)³

=2( 3 )³

=2(27)

=54

3 0

3 years ago

Read 2 more answers

How long would it take an object to stop if it is moving at 15m/s and has an acceleration -0.5m/s^2? Please show your work.

elena-14-01-66 [18.8K]

Time = 15/-0.5 = 14.5/-0.5 = 14.5s

The answer is 14.5s

Sorry no one would answer it sooner.

3 0

3 years ago

Air at 30°C and 2MPa flows at steady state in a horizontal pipeline with a velocity of 25 m/s. It passes through a throttle valv

erastovalidia [21]

Answer:

$V_2=159.9\ m/s$

$T_2=290.6K$

Explanation:

At initial condition

P=2 MPa

T=30°C

V=25 m/s

At final condition

P=0.3 MPa

Now from first law for open system

$h_1+\dfrac{V_1^2}{2000}=h_2+\dfrac{V_2^2}{2000}$

We know that for air

h= 1.010 x T KJ/kg

$1.01\times 303+\dfrac{25^2}{2000}=1.01\times T+\dfrac{V_2^2}{2000}$ -----1

Now from mass balance

$\rho_1A_1V_1=\rho_2A_2V_2$

We also know that

$\rho=\dfrac{P}{RT}$

$\dfrac{P_1}{RT_1}V_1=\dfrac{P_2}{RT_2}V_2$

$\dfrac{2}{R\times 303}\times 25=\dfrac{0.3}{RT_2}V_2$

$T_2=1.81V_2$ ----------2

Now from equation 1 and 2

$V_2^2+3673.749V-612916.49=0$

So we can say that

$V_2=159.9\ m/s$

This is the outlet velocity.

Now by putting the values in equation 2

$T_2=1.81\times 159.9$

$T_2=290.6K$

This is the outlet temperature.

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4 years ago

The surface air pressure on the planet mars is about 0.007 atm. if you were standing on mars, the surface air pressure would be

Lelu [443]

Surface air pressure is a consequence of the weight of the air acting on its surface. For example, if you are standing on Mars, the pressure around you is what you call the surface air pressure. Thus, that surface air pressure must be 0.007 atm.

5 0

3 years ago