The chemical formulas for their respective substances are the following:
Cadmium Sulfide: CdS
Sulfuric Acid: H₂SO₄
Hydrogen Sulfide: H₂S
This is a double replacement reaction where the substances of the reactants interchange to yield two products. The complete balance reaction would be:
<span>CdS (s) + H</span>₂<span>SO</span>₄<span> (aq) ----> CdSO</span>₄<span> (aq) + H</span>₂<span>S (g)
</span>
The other product is Cadmium Sulfate.
Correct formula for what?
<u>Answer:</u> The volume of hydrogen gas required for the given amount of ethylene gas is 113 L
<u>Explanation:</u>
At STP:
1 mole of a gas occupies 22.4 L of volume
We are given:
Volume of ethylene = 113 L
For the given chemical equation:

By Stoichiometry of the reaction:
of ethylene reacts with
of hydrogen gas
So, 113 L of ethylene gas will react with =
of hydrogen gas
Hence, the volume of hydrogen gas required for the given amount of ethylene gas is 113 L
Answer:
It will take 6.6 hours for 75% of the lead to decay.
Explanation:
The radioactive decay follows first order rate law
The half life and rate constant are related as

The rate law for first order reaction is
![time=\frac{1}{k}(ln[\frac{A_{0}}{A_{t}}]](https://tex.z-dn.net/?f=time%3D%5Cfrac%7B1%7D%7Bk%7D%28ln%5B%5Cfrac%7BA_%7B0%7D%7D%7BA_%7Bt%7D%7D%5D)
Where
A0 = initial concentration = 1 g
At= final concentration = 0.25 g (as 75% undergoes decay so 25% left]

Answer:
Option C is false statement. The half life of a second order reaction is not dependent on concentration.
Explanation:
Half life of a reaction is defined as the amount of time which is required for a reactant concentration reduced by half comparison to its initial concentration.
Half life of a second order reaction is depend on the initial concentration of a reaction, in contrast to 1st order reaction.