Answer:
The answer to your question is the second choice
Explanation:
Formula to calculate the heat of any substance
Q cal= mCcal ΔTcal
Formula to calculate the heat of a metal. The heat will be negative because it releases heat.
Qm = -mCmΔTm
Now equal both formula
Qcal = Q m
mCcalΔTm = -mCmetΔTmet
-Solve for Cmet
Cmet = -[mCcalΔTm] / mΔTmet
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Answer:
Freezing point solution = 70.131 °C
Explanation:
Step 1: Data given
Molality = 1.468 molal
A solution is created by dissolving biphenyl (C12H10) into naphthalene
Biphenyl is a non-electrolyte
Freezing point of naphthalene = 80.26 °C
Step 2: Calculate the freezing point depression
ΔT = i*Kf*m
⇒with ΔT = the freezing point depression = TO BE DETERMINED
⇒with i = the van't Hoff factor of biphenyl = 1
⇒with Kf = the freezing point depression constant of naphthalene = 6.90 °C/m
⇒with m = the molality = 1.468 molal
ΔT = 1 * 6.90 °C/m * 1.468 °C
ΔT = 10.13 °C
Step 3: Calculate the freezing point of the solution
ΔT = 10.13 °C
Freezing point solution = freezing point naphthalene - 10.13 °C
Freezing point solution = 80.26 °C - 10.129 °C
Freezing point solution = 70.131 °C
I pretty sure the answer is a
