No, it's not an ionic compound.
The distinguishing properties of ionic compounds are that they dissolve in water (water's polarity pulls the ions apart), are electrolytes (dissociate into ions, which conduct electricity), and have high melting points (it takes a lot of energy to separate the ions without water or other polar compounds). Since the unknown compound has the opposite of all these properties, it's not ionic.
From my understanding the correct answer would be phyical
Answer:
See explanation
Explanation:
According to Hund's rule, electrons must occur singly first before pairing takes place.
If I want to fill six electrons into orbitals, the filling of electrons will be as follows;
1s2 2s2 2p2.
The first four electrons are filled into the 1s and 2s levels having only one orbital each. The fifth and sixth electrons are filled into 2p orbitals. The 2p level have three degenerate orbitals. The two electrons are singly filled into each of the degenerate orbitals in accordance to Hund's rule.
Answer: 0.0164 molar concentration of hydrochloric acid in the resulting solution.
Explanation:
1) Molarity of 0.250 L HCl solution : 0.0328 M
Moles of HCl in 0.250 L solution = 0.0082 moles
2) Molarity of 0.100 L NaOH solution : 0.0245 M
Moles of NaOH in 0.100 L solution = 0.00245 moles
3) Concentration of hydrochloric acid in the resulting solution.
0.00245 moles of NaOH will neutralize 0.00245 moles of HCl out of 0.0082 moles of HCl.
Now the new volume of the solution = 0.100 L +0.250 L = 0.350 L
Moles of HCl left un-neutralized = 0.0082 moles - 0.00245 moles = 0.00575 moles
Molarity of HCl left un-neutralized :
0.0164 molar concentration of hydrochloric acid in the resulting solution.
