HELP ASAP<br><br><br><br> 8 5/12÷ 1 3/4

A number minus the product of 36 and its reciprocal is less than zero. Find the numbers which satsify this condition

svetlana [45]

Answer:

A number minus the product of

4

and its reciprocal is less than zero. Find the numbers which satisfy this condition.

AAny number less than

−

2

or between

0

and

2

BAny number between

−

2

and

2

CAny number less than

2

DAny number between

0

and

2

Solution

Let the number be x

Then

x

−

(

4

×

1

x

)

≤

0

⇒

x

≤

4

x

⇒

x

2

≤

4

⇒

|

x

|

≤

2

⇒

−

2

≤

x

≤

2

Step-by-step explanation:

5 0

3 years ago

in the following ordinary annuity interest is compounded with each payment and the payment is made at the end of the compounding

RSB [31]

Answer: $59313.58

Step-by-step explanation:

Formula to find the accumulated amount of the annuity is given by :-

$FV=A(\frac{(1+\frac{r}{m})^{mt})-1}{\frac{r}{m}})$

, where A is the annuity payment deposit, r is annual interest rate , t is time in years and m is number of periods.

Given : m= $2000 ; m= 1 [∵ its annual] ; t= 10 years ; r= 0.06

Now substitute all these value in the formula , we get

$FV=(4500)(\frac{(1+\frac{0.06}{1})^{1\times10})-1}{\frac{0.06}{1}})$

⇒ $FV=(4500)(\frac{(1.06)^{10})-1}{0.06})$

⇒ $FV=(4500)(\frac{0.79084769654}{0.06})$

⇒ $FV=(4500)(13.1807949423)$

⇒ $FV=59313.5772407\approx59313.58 \ \ \text{ [Rounded to the nearest cent]}$

Hence, the accumulated amount of the annuity= $59313.58

8 0

3 years ago

The volume of a spherical balloon is increasing at the rate of 25cm^3/min, how fast is the radius increasing when the radius is

S_A_V [24]

Answer:

So the radius is increasing at $\frac{1}{64\pi} \frac{\text{cm}}{\text{min}}$ .

This is approximately 0.00497 cm/min that the radius is increasing.

Step-by-step explanation:

$V=\frac{4}{3}\pi r^3$

The volume and radius are both things that are changing with respect to time.

So their derivatives will definitely not be 0.

Let's differentiate:

$V'=\frac{4}{3} \pi \cdot 3r^2r'$

I had to use constant multiple rule and chain rule.

We are given $V'=+25 \frac{\text{cm^3}}{\text{min}}$ and $r=20 \text{cm}$ .

We want to find $r'$ .

Let's plug in first:

$25=\frac{4}{3}\pi \cdot 3(20)^2r'$

$25=\frac{4}{3} \pi \cdot 3(400)r'$

$25=\frac{4}{3} \pi \cdot 1200r'$

Multiply both sides by 3:

$75=4 \pi \cdot 1200r'$

$75=4800 \pi r'$

Divide both sides by $4800 \pi$ :

$\frac{75}{4800 \pi}=r'$

$\frac{1}{64 \pi}=r'$

So the radius is increasing at $\frac{1}{64\pi} \frac{\text{cm}}{\text{min}}$ .

This is approximately 0.00497 cm/min that the radius is increasing.

5 0

3 years ago

Read 2 more answers

Can I get help with this?

Trava [24]

Answer:

arc AE = 125 deg

Step-by-step explanation:

As the property of angle at the center O of a circle:

angle AOE = arc AE

=> arc AE = 125 deg

Hope this helps!

6 0

3 years ago

Hii, this geometry, please help haha!!

frutty [35]

Answer:

its 6

Step-by-step explanation:

(16x+5) = 1

50 - 45 = 5

5+1=6

4 0

3 years ago

Read 2 more answers

HELP ASAP 8 5/12÷ 1 3/4